Recent content by Jason76

Hints on here at a starting strategy?

What would be f(x) - given the below information? K + 2K + 3K + 4K + 5K + 6K = 1 is the correct format so 21K = 1 so K = \dfrac{1}{21} f(x) = \dfrac{1}{21}x ??

Contacted the professor. K + 2K + 3K + 4K + 5K + 6K = 1 is the correct format so 21K = 1 so K = \dfrac{1}{21}

It seems like a long time ago, the professor said something about differentiation and also used Wolfram Alpha.

K(x^{6}) = 1 \dfrac{K(x^{6})}{x^{6}} = \dfrac{1}{x^{6}} where x \ne 0 K = \dfrac{1}{x^{6}} Actually, here is the original problem: Next finding K is needed. Sorry if in wrong section. This is for probability.

What is the value of K? K(x^{6}) = 1