Please help me explain how to solve this to find the unilateral laplace transform
x(t)=tu(t) - (t-1)u(t-1) - (t-2)u(t-2) + (t-3)u(t-3)
I know the part tu(t)
as a(t) = u(t) --> 1/s
then b(t) = tu(t) ---> - d/dx a(t) = 1/s^2
But for those (t-1), (t-2) in front u(t), how to solve...
ops, sorry is power signal, but how to evaluate the integration
is it take the whole equation as X(t), then square the whole equation? or do integrate it one by one?
Almost, can you help me on the find the fundamental period of x(t) = sin^3(2t)?
Also, beside the question above, here another one
Find the energy for the signal:
x(t) = 5 cos(pi*t) + sin (5pi*t), -infinity<t<infinity.
How to apply the energy formula to this one? is it the X^2(t) in the energy formula substitute with this?
[5 cos(pi*t) + sin (5pi*t)]^2
or the cos and the...
x(t) = cos^2(2*pi*t)
=1/2[1+cos(4*pi*t)
so w=2pi/T
4pi = 2pi
T=0.5, is I do the correct way?
But how about
x(t) = sin^3(2t)?
I do like this:
1/4[3sin 2t + sin 6t]
2 = 2pi/T
T = pi
6 = 2pi/T
T = pi/3
The answer is 1/pi. How to do this?
I always have troubles to determine discrete signal whether periodic or nonperiodic and its fundamental period, even the most basic one x[n] = Cos(2n) and x[n] = Cos(2n\pi)
I know for periodic discrete signal need to follow x[n+N] = x[n]
But I don't know how to apply and relate it like...