How Do You Solve the Unilateral Laplace Transform for Delayed Functions?

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SUMMARY

The discussion focuses on solving the unilateral Laplace transform for the function x(t) = tu(t) - (t-1)u(t-1) - (t-2)u(t-2) + (t-3)u(t-3). The user identifies the Laplace transform of tu(t) as 1/s² and seeks guidance on handling the delayed functions (t-1)u(t-1) and (t-2)u(t-2). Key insights include utilizing the property of delays in the Laplace transform and deriving the relationship from the definition using the substitution t' = t - a.

PREREQUISITES
  • Understanding of unilateral Laplace transforms
  • Familiarity with the Heaviside step function, u(t)
  • Knowledge of differentiation in the context of Laplace transforms
  • Basic calculus, particularly integration techniques
NEXT STEPS
  • Study the properties of the Laplace transform, specifically the effect of delays
  • Learn how to derive the Laplace transform of delayed functions using the definition
  • Explore examples of Laplace transforms involving piecewise functions
  • Practice solving Laplace transforms of functions with multiple delays
USEFUL FOR

Students and professionals in engineering, mathematics, and physics who are working with Laplace transforms, particularly those dealing with delayed functions in system analysis and control theory.

jasonjinct
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Please help me explain how to solve this to find the unilateral laplace transform
x(t)=tu(t) - (t-1)u(t-1) - (t-2)u(t-2) + (t-3)u(t-3)

I know the part tu(t)
as a(t) = u(t) --> 1/s
then b(t) = tu(t) ---> - d/dx a(t) = 1/s^2

But for those (t-1), (t-2) in front u(t), how to solve these?

Please help me, thank you very very much
 
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Look up how a delay affects the Laplace transform. It's usually one of the properties listed for the transform.

Alternatively, you could derive the relationship for yourself from the definition. Start with

[tex]L[f(t-a)u(t-a)] = \int_0^\infty f(t-a)u(t-a)e^{-st}\,dt[/tex]

and use the substitution t'=t-a.
 

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