Have you gotten from:
\frac{\omega (1+\tan^{2}\delta)+2\lambda\tan\delta}{\lambda -\zeta -(\lambda +\zeta)\tan^{2}\delta}=\frac{\tan\delta +\tan\phi}{1-\tan\delta\tan\phi}
to:
\delta=\arctan...
Hi hunt_mat,
I have already, along other approaches, done that. With your proposal, i.e. invoking the relations:
\sin 2\delta=2\sin\delta\cos\delta,\quad \cos 2\delta=1-2\sin^2\delta
and
\tan\delta=\frac{\sin\delta}{\cos\delta},\quad...
Hi guys,
I need some help. I have the following modulation equations:
\Re:-\zeta a+\lambda a\cos 2\delta-\eta \cos (\delta+\phi)=0
and
\Im:\omega a+\lambda a\sin 2\delta-\eta \sin (\delta+\phi)=0
which, with proper manipulation (i.e. by squaring and adding and/or diving them with each...