Recent content by JavaJoeUK2011

A horizontal force of 80N acts on a mass of 6Kg resting on a horizontal surface. The mass is initially at rest and covers a distance of 5m in 0.92s under the action of the force. Assuming there are no energy losses due to air resistance and therefore that the acceleration is constant. 1.Plot...

So velocity would be v = 11.81 x 0.92 = 10.8652 so acceleration would be a = v-u/t = 10.8652-0 / 0.92 = 11.81

Do you mean w=fd = 80=f x 5 = 400 Is that correct?

So if i rearrange the formula d = (1/2)at2 = (1/2)(13.33m/s2)(0.92s)2 = 5.64m to give me d = (1/2)at2 = (1/2)(x m/s2)(0.92s)2 = 5m x = 6250/529 = 11.81474 m/s2 d = (1/2)at2 = (1/2)(11.81474m/s2)(0.92s)2 = 5m would that also give me the correct answer?

would w=mas give me it =6 x 13.33 x 5 = 399.9?

1. Helo all, A horizontal force of 80N acts on a mass of Kg resting on a horizontal surface. The mass is initially at rest and covers a distance of 5m in 0.92s under the action of the force. Assuming there are no energy losses due to air resistance and therefore that the acceleration is...