Recent content by JayDub

E mechanical = W friction? I do not quite see how that will help me... PE = KE = Fd? mgh = .5(m)v^2 = 9.4N(d) I do not have a distance...

Well, what about in the case such as: A 5kg block initially traveling at 11 m/s up a 30 degree incline. A frictional force of 9.4N acts on the block as it moves up the incline. What is the maximum height the block will reach?

Hey there, I have been studying for my physics final coming up and I am constantly getting stuck on the stuff that we started at the beggining of the year. Such as this question: A 6 kg object is projected directly upwards with an initial speed of 15 m/s. This object experiences an average...

I am sorry, I do not quite follow. Isn't the netforce up AND down?

Hey there all of you. I am doing some studying for my final for physics and i have come across this question. I thought it was easy but it is not working that way. The question is. A 4kg block (held by a block) is accelerating down at 3 m/s/s, what is the tension of the rope? So I am...

Hey There, I am studying for my exam here coming up in two weeks and I came across a question with electric field. Now I can figure it out (E = kq/ r^2) but I was wonder which direction does it travel in? For example if the question was something like: A uranium nucleus contains x protons...

Thus graphing, gives me an x value of 8 and a perimiter of 32.

wait a minute... If Side 1: x Side 2: 64 / x To find the smallest area couldn't I graph 2(x) + 2(64 / x) and find the smallest perimiter?

Lol, I understand why it is giving me that (because the x's cancel) which I am sure you know. If I had the inverse of this question, something like. The perimiter of a rectangle is 100 cm. What is the largest area it can have? I would go Side 1: x Side 2: 50 - x Graphing: x(50-x) thus at...

I am trying to remember how I would go about solving an equation like so. What is the smallest perimiter of a rectangle with area of 64 cm^2. I know I can use the graphing calculator. So I know there are two sides, x and 64 / x. If I try and graph x(64/x) I just get a straight line...

Actually, I think I may have it, would this be it? [bare with me while I try to do that tex graphic stuff] Fx = Fn sin(\theta) + mew Fn cos(\theta) Fy = Fn cos(\theta) - mew Fn sin(\theta) - mg which to find the Fc we would solve it to Fc = \sqrt{\frac{r g (sin(\theta) + mew...

Hey there, so we started learning centripical forces today. We learned the basic formulas: Fc = \frac{v^2}{r} and Fc = m \frac{4 pi^2 r}{T^2} http://elarune.net/admins/josh/q-angle.jpg That is the question, I had to get rid of stuff that i had written in, probably not...

But then wouldn't either this horizontal Fn or the grounds Ff be 0 since one of them is the pivot point?

But for question 6, couldn't you think of all the forces as torques like I did above? Also, for question 5, I gave the wrong image, it should be http://www.elarune.net/admins/josh/q17.jpg

Question 6: Ok, so the torques would be from his Fg, Fg of the ladder and the Ff, would I go: Tccw = Tcw 60kg(9.8m/s/s/)(1m)sin30 + 5kg(9.8m/s/s)(2m)sin30 = Ff(4m)sin60 294Nm + 49 Nm = Ffsin60 343 Nm = Ff(4m)sin60 Ff = 99 N Question 1: Tcos45 = Fg T = Fg / cos45 T = (2kg)(9.8 m/s/s) / cos45...