Recent content by Jayjayjay

is "Ka / [H+] = (1-θ) / θ" where I need to start, or is that where I initially messed up.

Didn't I do that with this θ = ([H+] / Ka) + 1 ⇒ θ = ([H+]+[Ka]) / [Ka]

Well I thought to solve for theta meant to get theta by itself on one side of the equation and have everything else on the other. you're saying express theta using the other variables ( Ka / [H+] )? so does that mean just to simplify the part I was correct up to, to get... [H+]/Ka = θ - 1

So trying to go from 1/θ = ([Ha]+[A-]) / [Ha] ⇒ 1/θ = [Ha]/[Ha] + [A-]/[Ha] is wrong because that is the part that I was skeptical about.

θ = ([H+] / Ka) + 1 ?

Ka / [H+] = [A-] / [HA] 1 / θ = ([HA] + [A-]) / [HA] ⇒ 1 / θ = 1+ ([A-]/[HA]) ⇒ (1-θ) / θ = [A-] / [HA] Ka / [H+] = (1-θ) / θ ⇒ θ = 1 + Kaθ / [H+]

Should I not be setting θ=[HA]/Ca since Ca=[HA] + [A-], or Am I suppose to try substituting them into Ka separately?

they will have equal amounts when dissociated?

They will always reach some sort of equilibrium, when they are multiplied they will always equal 1*10^-14?

So using that variable you could do "theta = HA /Ca" which you could turn into "(theta)(Ca) = HA" and then just substitute to get Ka = [(H+)(A-)] / [(ca)(theta)] ? I'm having a hard time thinking of another way to implement it.

Is it the "Theta = [HA] / ([HA]+[A-])" that skelly posted? since that would give the fraction of protonated to unprotonated?

[A-] is the concentration of deprotonated form of the acid, and [HA] is the concentration of the protonated form of the acid The theta is suppose to be the fraction of acid molecules that is protonated, so its none of these values right? since [HA] and [A-] are concentrations in mol/L, while...

Something like (theta) = (Ka)(HA) / (A-)?

Homework Statement The dissociation constant Ka for the acid-base reaction HA-->(H+)+(A-) is given by Ka = products / reactants; but instead of listing Ka, people generally list pKa = -logKa (where log indicates the 10-base logarithm). Similarly, instead of using [H+], people generally use pH...

Homework Statement Given the functions Q(v,w) and R(v,w) [/B] K = v(dQ/dv)r and L = v(dQ/dv)w Show that (1/v)K = (1/v)L + (dQ/dw)v (dW/dv)r I have the problem attached if for clarity of the information. Homework Equations I assume everything is given in the problem. The Attempt at...