Recent content by jayjones01

You are right, I didn't really check my H[1,2,3] matrix and I did a careless mistake writing it down, that's why my 3 qubit examples were wrong and I could not see any logic in them :-p The last paragraph explains it very well and I now understand why |0000>+|1111> generates a mix of even bit...

Thanks a lot for your reply SpectraCat. Yeah I thought it should be due to interference, but I can't really understand why it works that way. I'm studying some error correction schemes for quantum circuits and there are some 4 qubit circuits to produce certain mixture of states. I wan't to...

Forgive my lack of formalism, but when i say a mix of 0 and 1, I am actually referring to the state: \left| \psi\right\rangle = \frac{1}{\sqrt{2}} \left( \left| 0\right\rangle + \left| 1\right\rangle \right) The same applies to the state of all 8 combinations with 3 qubits i mentioned, i...

It's a system with 3 qubits, hence the operator H[1,2,3]. When I have 1 qubit, let's say a \left| 0\right\rangle, I understand that a Hadamar gate will create an equally probable quantum state that mixes \left| 0\right\rangle and \left| 1\right\rangle, cause a Hadamar gate combines states...

Lets say I have the following quantum state: \frac{1}{\sqrt{2}}\left| 000\right\rangle + \frac{1}{\sqrt{2}}\left| 111\right\rangle And that I apply a Hadamard gate to each of these qubits (H[1,2,3]). The math shows that the resulting state will be: \frac{1}{2}\left| 000\right\rangle +...