Recent content by JayRemmy

  1. J

    Kinetic Energy of the Products of Nuclear Reaction?

    Ahh, I just got the right answer, I took (13.00335+2.0141)-(14.003241+1.008664) = .005546 and .00546* 931.5 = 5.1661 and 5.1661+36.3 = 41.46, which was the correct answer. So for a problem like this I just take the Q value, then add that to the incoming KE value?
  2. J

    Kinetic Energy of the Products of Nuclear Reaction?

    Ok, so I took; 36.3+(13.00335*931.5) = 12148.9 MeV and (14.003241*931.5)+(1.008664*931.5)= 13983.6 and 12148.9-133983= 1834.67 (wrong answer) so I tired taking out the neutron rest mass because I assume it's moving afterwards... through the same process I got 895.098 (wrong answer)...
  3. J

    Kinetic Energy of the Products of Nuclear Reaction?

    I understand but can I find momentum for C-13 if there is no velocity? The only thing I can think of is to do KE=p^2/2m, but that doesn't give me the right answer either. I ended up getting 10261.7 MeV.
  4. J

    Kinetic Energy of the Products of Nuclear Reaction?

    Homework Statement Calculate the total kinetic energy of the products of the reaction d+C-13 --> N-14 + n if the incoming deuteron (d) has 36.3 MeV. Homework Equations Q=(Parent Mass - Daughter Mass - Decay Particle Mass)*c^2 1u = 931.5 MeV C-13 = 13.00335u N-14 = 14.003241u Neutron...
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