Recent content by JAZZ541

Ty very much!

Homework Statement Hi all, I have solved these problems just wanted to see if it's all ok problem 1: a trolley starts at the lowest point of a diagonal plane with a 20m/s speed. Its acceleration is 4m/s^2 going downhill, the trolley goes up then slows until it reaches 0 speed and then goes...

Then: mu = sin37° = 0.6 Ty very very much for your patience and guidance!

TY! a = 0 ? mgsinα = T = f = mumg ?

Thank u for your patience! I have this: 1. m1(A)g = m2(B)g = 20Kg X = 1m mag • sinα – T = m1a T = m2a mag • sinα -T + T = m1a + m2b 200 • 0.60 = a(m1 + m2) a = 120/40 = 3m/s X = V0T + at^2 /2 1 = 0 + 3t^2/2 2 = 3t^2 t = 0.816s 2. T = m2a T = 20 • 3 = 60N there are two more...

I'm sorry I had to go ill try and work on it some more and come back later

f - friction ohh, but they said smooth surface, so no friction and T1 = T2?

Ty! Is this correct? btw angle is 37 and not 27

Homework Statement Log A weighs 20Kg is laid on a diagonal smooth plane with a diagonal angle of 27 37 degree, log A is tied by a rope to the head of the plane and there through a wheel with no friction the rope descend vertically to the bottom of the plane and through another friction-less...

tyvm! yes, I wondered about that but the other way around, thought it will travel less, it seemed to make sense intuitively - that heavier objects will travel less distance, obviously it doesn't - why? is that due to inertia as you mentioned? ty!, noted!

Homework Statement Hi, would like to get a feedback on my answer to this question, did I do it right? In part 2 of the question is there another way to calculate distance with friction? the question is: a disc is moving on icy surface has an initial speed of 12m/s 42m until it stops 1. what...

haha, too much thinking made me a bit slow I guess, ty for your help! unfortunately I'm sure Ill need it again lol

haha you make my efforts look so complicated when there's a clean simple answer and I calculated when calc is on degree, that's how my teacher wants it, I thought I can't use Pythagoras I can't remeber why now, very new to all of this, is what I did legit at all? cause if its is (-) then result...

think I made it:Tanα = 5/0.8 → α = 80.9° Y = 5sin80.9° = 4.937 X = 0.8cos80.9° = 0.126 4.937 + 0.126 = 5.06m/s

Vy(t) = V0y – gt 0 = V0y – 10m/s2 • 0.5s V0y = 5m/s is that right?