I totally thought there was no easy solution and started doing inclusion-exclusion and stuff, but apparently it is easy. And I double checked that there exists a distribution satisfying 38 students advancing i.e 37 students get 4 right, 1 student gets 3 right and 62 students get 2 right. You can...
Thanks for your helps. I got it. There are 275 right answers. Each student gets two right answers. The remaining 75 are distributed so that the number that pass is minimized, 2 question to 37 students and the remaining question to the 38th student.
Can someone give me general guidance on how to solve this problem (it's not homework):
There were 100 students taking a math contest consisting of four questions. 90 of them got problem 1 correct. 85 of them got problem 2 correct. 60 of them got problem 3 correct. 40 of them got problem 4...