Recent content by Jebus_Chris

I think I finally understand this + and -. I picked the current going to the right around the loop. Labeled each element with a plus and minus, current entered the plus so each one is positive. Blah blah balh, it all worked out.

http://imgur.com/6aAMV So I need to find the current labeled as a function of time. THe switch opens at t=0 and I drew the circuit after the switch opens. I found the initial current to be -4 and the voltage on the capacitor to be 8. I'm having trouble trying to find di_L(0)/dt. I...

Ok, so then you're saying that there is 2mA of current traveling up [i(0) = -2] through the inductor?

So then are you saying that you remove the current source as well since the voltage around it is zero?

I'm not sure what happens when you replace the inductor with a short circuit. The current source is what throws me off. One thought I had was that you can remove the 6 and 2 kohm resistors, but then I don't know what ahppens to the current source. http://imgur.com/lks7y Thanks

Yes, sin theta increases as the angle increases, therefore the acceleration increases as the angle increases.

Is the car stationary when it starts accelerating?

You have an initial speed in the y direction, 60sin60.

v^2 -4.165 = (v^4-86612.49)^1/2 v^2 - x = (v^4-y)^{1/2} v^4 - 2v^2x + x^2=v^4-y -2v^2x + x^2=-y v=\sqrt{\frac{x^2+y}{2x}} there u go

You can add, divide, subtract equations when dealing with systems.

Once you square it you will be left with only 1 V term. It may be easier to replace your constants with variables. Then just substitute them in once you find V.

A number squared is always positive. So if you plug in -10 you get sqrt(100) which is 10. When you cancel out the square and the square root in a problem you do that because you're looking for the principle root aka the positive one.

You may have to take the y component of the normal force.

Only part of the hamster's weight is measured on the scale. Part is directed down the ramp which doesn't measure on the scale but the other part pushes the ramp down and is measured on the scale.

Draw a picture. Find the area of the bottom trapezoid and top triangle then add them.