It is moving down with 2v right? So if it were not moving up it would rotate with 2v/r. I think the upward movement does change it. The upward movement gives the left, middle and right side a velocity of v upwards. While the rotation gives the left side a velocity of 2v downwards and 2v upward...
Okay, that one rotates with a velocity of 2v but translates also upwards. So what I'd say is that the left side moves with 2v-v, the middle v and the right side 2v+v.
ω*r gives the velocities at the left and right side of the pulley S, this gives a v upwards for the right side and v downward for the left side. This is the velocity by rotation, but the pulley also translates with a velocity v. This the translation v is for the left middle and right side the...
Is it because pulley S performs a translational motion as well as a rotation?
Pulley R (and all other pulleys in the same row) on the other hand only perform a rotational motion and no tranlational motion. But because the rope between S and R is the same that rope moving with a velocity of 2v...
First of all thank you for your response.
I'd say that the leftmost velocity is equal to 0, because that part is connected to the block and doesn't move.
But for the one between S and R I would guess that one is 2v, because it's kind of the same as a 'wheel without slip' situation. The center...
Further given:
- every beam is infinite stiff
- pulleys are massless
- cables don't stretch, no slip, and frictionless.
-Every pulley has a diameter D except pulley Q. Pulley Q has diameter 0.5*D
So what I don't understand is how to calculate/determine the velocity at R and S. Can someone help...