Yes Jeff has my basic description covered quite well. Frictionless hole through the diameter with a rod inserted into that hole. basically tip the cylinder onto one of its flats, then insert a rod through it from left to right, directly through the middle of the cylinder. then tip it back up...
I am playing with math and physics during my off-time at work, and I am wondering how to calculate a specific force, or if I am even looking at it correctly. Here it is.
A rod through a cylinder's radius so that if it is off to one side causes rotational force equal to the difference in foot...
Okay, here is my hypothetical situation. Let's say there is a cylinder and we're looking at it with the round side facing us. Its diameter is 48in. There is a 48in rod going through that cylinder(with the ends shaped so that it conforms to the circumference of the cylinder) from the left side...