Recent content by JenniferBlanco

Thanks Mathdope and dynamicsolo!

OK, so I differentiated the equation and got 2/x Then I plugged 1 into x, so our slope is 2 while the y value is --> -2 + 0 = -2 and the equation i got is --> y+2=2(x-1) is that right? Also, are my first two parts right? -Jen

Hi, Can someone please help me out and guide me? Homework Statement http://img167.imageshack.us/img167/3892/dscn8321rn1.jpg Homework Equations Shown aboveThe Attempt at a Solution a) f(x) = -2 +ln(x)^2 f'(x)= 2/x Ans: All real numbers except for 0 b) -2 +ln (x)^2 =0 ln(x)^2= 2...

aaah yes. I was writing it down and was wondering how 6=18. Sorry for the error and Thanks for the help. :)

Thank you! so, (8 +2c) - c = 18 and c = 10 that gives me--> f(x)= 12x^2 - 6x + 10

when x=1 then I got c when x=2 then I got 8+2c

yes, i edited it before you replied.

x^4 - x^3 + cx

I tried using (iii) and this is what I got - f(x) = 4x^3 -3x^2 + c then I plugged in 2 and 1 and got - (32-12+c) - (4-3+c) = 18 but then c will cancel out. I am sure I am doing this wrong. please guide me

Homework Statement I don't know how to make the integral sign :frown: so I am took a picture of the question. http://img99.imageshack.us/img99/4139/mathquestional7.jpg Homework Equations Equations are located in the above img.The Attempt at a Solution I first integrated the first derivative...

cool! :cool: Thanks for all the help Rainbow Child! really appreciate it! :-p

ohhh. then the Area = 1/2 * 8.944 * 4/sqrt(5) = 7.999 which is = 8units^s [our earlier answer :smile:]

So area of the triangle = 1/2 * 8.944 *4 = 17.88 units^2 I got the midpoint of QR as (1,5) and the distance from there was 4. So my final answer for the area of the triangle is 17.88 units^2 :-p

:biggrin: The max value I get is when x_0=1 and D would then be 4/sqrt(5)

yes, you're right