Help Solve Optimization Problem

[JenniferBlanco]

Good!

Now what's the maximum value of $$d$$? For which $$x_0$$ you obtain that?

The max value I get is when $$x_0=1$$ and D would then be 4/sqrt(5)

 

[Rainbow Child]

Very nice! Let us now be proud of ourselves and calculate the area of the triangle!

 

[JenniferBlanco]

Very nice! Let us now be proud of ourselves and calculate the area of the triangle!

So area of the triangle = 1/2 * 8.944 *4 = 17.88 units^2

I got the midpoint of QR as (1,5) and the distance from there was 4.

So my final answer for the area of the triangle is 17.88 units^2

 

[Rainbow Child]

No, the distance is $$d=\frac{4}{\sqrt{5}}$$=height. You don't need the midpoint

 

[JenniferBlanco]

ohhh. then the Area = 1/2 * 8.944 * 4/sqrt(5) = 7.999 which is = 8units^s [our earlier answer ]

 

[Rainbow Child]

Bravo!

Archimedes was right!

 

[JenniferBlanco]

cool! Thanks for all the help Rainbow Child!

really appreciate it!