Recent content by Jewelz
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Non-Constant Acceleration Problem
Your assumption is correct. After integrating the acceleration function with respect to time, with the bounds of the integral from ##0## to ##t##, I obtained the function ##t^3/3## for the velocity. Integrating that, from 0 to t for the integral, I got ##t^4/12##, and plugging in ##t## (10...- Jewelz
- Post #4
- Forum: Introductory Physics Homework Help
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Non-Constant Acceleration Problem
Homework Statement A new Tesla is designed that can perform a non-constant acceleration for 10 seconds of motion. The magnitude of the acceleration is given as a(t) = 1 m/s4t2 Starting from rest, how far does the car travel over this 10 second interval? Homework Equations This is what is...- Jewelz
- Thread
- Acceleration Displacement
- Replies: 5
- Forum: Introductory Physics Homework Help
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Moment of Inertia of a Spinning Record with a Hole in Center
Looking back over at what I did, I don't really know what I should be changing about the density. Other than simply rearranging the equation to m=ρV, then knowing volume of a disk would be πR1^2 - πR2^2, and plugging that in with the equation remaining from the integral, it still cancels out to...- Jewelz
- Post #12
- Forum: Introductory Physics Homework Help
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Moment of Inertia of a Spinning Record with a Hole in Center
I just tired it out, and I got an answer of I = 0.5M((R2)^2 - (R1)^2), but I am not sure if that is completely right.- Jewelz
- Post #9
- Forum: Introductory Physics Homework Help
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Moment of Inertia of a Spinning Record with a Hole in Center
I do apologize for that. I am new to the site and have never used LaTeX. I tried it for a little, but for unknown reasons, I kept getting errors with it. I cleaned up the relevant equations portion. Everything in my attempt is basically just plugging numbers straight into those equations. The...- Jewelz
- Post #7
- Forum: Introductory Physics Homework Help
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Moment of Inertia of a Spinning Record with a Hole in Center
Ahhhh, that makes a lot more sense. So other than changing the radius in the equation for IDISC, which would just be the radius of the whole disc (3.5 in) minus the radius of the hole (0.75 in), which would give a new effective radius for IDISC or 2.75 in, everything else looks to be okay?- Jewelz
- Post #5
- Forum: Introductory Physics Homework Help
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Moment of Inertia of a Spinning Record with a Hole in Center
Yes, actually, that was a previous part of the problem, getting to the 0.5MR^2. I just have never had a problem where there was a hole that needed to be accounted for- Jewelz
- Post #3
- Forum: Introductory Physics Homework Help
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Moment of Inertia of a Spinning Record with a Hole in Center
Homework Statement A 45 RPM record is a disk with a wide hole in the center. The mass of such record is 45g. It is 7 inches in diameter, and the hole in the center has a 1.5 inch diameter. (Sorry for the odd units, this was the way it was given). Find the moment of inertia of the 45 RPM...- Jewelz
- Thread
- Center Disc Hole Inertia Moment Moment inertia Moment of inertia Spinning
- Replies: 13
- Forum: Introductory Physics Homework Help