Recent content by jgridlock

Alright, my final question is about the non mathematical part. Letters b-f (Correct me if I am wrong). When the balls are released the top one should reach a max height and then float above the second one because they repel each other. But then what happens when the friction comes into play?

Should the new equation be: 1/2(.012)(0) + (.012)(9.8)(.06) + (8.99e9(.45e9*.45e9)/(r)) = .03739725 Where I solve for r?

Thanks for all the help, sorry I need so much support.

So the number I just calculated is for the TME at r initial?

Okay so the r is going to be equal to .06m. The velocity at the initial position is zero, so I set v = 0? 1/2(.012)(0) + (.012)(9.8)(.06) + (8.99e9(.45uC*.45uC)/(.06)) = .03739725

So your saying that both h and r should be .03m? And I am solving for velocity? 1/2(.012)(v^2) + (.012)(9.8)(.03) + (8.99e9(.45uC*.45uC)/(.03))?

TME = 1/2mv^2+mgh+k((q1*q1)/r)

Convert cm to m. 3cm = .03m And g to kg. 12g = .012kg Alright, next step?

Electric Potential Energy: PE = k((q1*q1)/r) A pair of point charges separated by a distance

I wouldn't know any others. A guess would be charge?

Kinetic energy? KE = 1/2mv^2

PE = mgh?

I could use a little more guidance than that. What kind of process should I follow to solve part A?

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Homework Statement A block of copper having a density of 8.90 g/cm^3 has an apparent mass 120g in water and 116g when submerged in a liquid. What is the density of the liquid? Homework Equations The Attempt at a Solution Don't know if there's a better method, but here is the way I did it...