Recent content by jhg12345

Yea, I know. Thanks for the help.

ok thanks for the help so far, but I am still stuck.

Yea, that's what I did and I got a matrix, but I can't get a matrix with a row of all zeros.

Thanks so much guys

Yea, I wasn't solving for a,b and c before. Thanks for clearing that up.

So vector (1,-2,1) will be just one of the possible normals. Gotcha.

I subtracted a + b + c = 0 from 2a + b = 0 and got a = c.

Yea, but the section we've done so far doesn't use cross product. And can't the matrix be zero if the column vectors (that you solve for) cause the left side of the matrix to equal 0?

Put both vectors in a matrix and set it equal to 0?

Is the normal n = (-1, 0, 1)? I subtracted the two vectors and plugged the result into the dot product equation and set it equal to 0.

Homework Statement Give the Cartesian equation of the following hyperplane: The plane spanned by (1,1,1) and (2,1,0) and passing through (1,1,2)Homework Equations The Attempt at a Solution I keep getting 4 = -2x(sub1) + -2x(sub2) +x(sub3). However, the answer is x(sub1) - 2x(sub2) + x(sub3) =...

Okay I think I figured it out thanks for the help gagga

They're the same!

ax_0+by_0+cz_0 = 0

It's a(sub1)x(sub1)+a(sub2)x(sub2)+a(sub3)x(sub3) = c