Recent content by JimCrown

The first calculations are all correct and follow the formula I was given. I am having trouble when I reach here (mainly how to find out the volume of concrete) I believe it to be 1.5 m^3 I am not equating torque with force I just think we are having a serious miscommunication:I am not sure if...

That is part of the formula I was given. R is the Force: R = pgyA = 1000*9.81*0.81*5.6895 = 45.2093 kN I meant to put EF as FE. And EA is the middle of the gate. The units are fine after checking through everything and so are the sums until a certain point when I do not know what I am doing.

Sorry if it is unclear: Sine 140 = AC/0.9m AC = 0.9m*sin140 = 0.579m This is sin140 = AC / 0.9m So I rearranged the equation so AC becomes the subject so it becomes AC = 0.9m * sin140 = 0.579mI divided it by (1000 / 9.81) to convert the kN into kg Then, I could find the volume as I had the...

Even without the metres I am still getting the same answer which, I do not think is correct900mm = 0.9m Sine 140 = AC/0.9m AC = 0.9m*sin140 = 0.579m y = 5.4m + (0.579m/2) = 5.6895m A = 0.9m*0.9m= 0.81m^2 R = pgyA = 1000 kg/m^3*9.81m/s*0.81m^2*5.6895m = 45209.3 N = 45.2093 kN...

Sorry my mistake that should be unitless then

Sorry, I believe that Sine function has no units as it is ratio of lengths. It is known to be sin θ As sin is defined as the ratio between the opposite leg and the hypotenuse, its dimension is length / length =1 (i.e. it is dimensionless).

Sorry for that again. sin140 is 0.643 to 3dp

Sorry if it was not clear: sin140 degrees (140°) 140^2 is 140 squared 0.413 metres

900mm = 0.9m Sine 140 = AC/0.9m AC = 0.9m*sin140 = 0.579m y = 5.4m + (0.579m/2) = 5.6895m A = 0.9m*0.9m= 0.81m^2 R = pgyA = 1000 kg/m^3*9.81m/s*0.81m^2*5.6895m = 45209.3 N = 45.2093 kN D/Magnitude = sin^2 (IGG + A (y/sin)^2 / A *y) sin140^2 = 0.413m IGG = bd^3 / 12 = 0.9m*0.9m^3 /...

I don't see any more errors after following the formulas I was given. I know you have just stated you will not point them out but, I have been trying and trying and cannot see them. It is not like I have just posted the question with no serious attempt at attempting or answering it. I was...

thanks for letting me know

I have tried again. The only error I found was the D-y value from a previous attempt I forgot to replace the old y value with the new y value. How is this? Sine 140 = AC/0.9 AC = 0.9*sin140 = 0.579m y = 5.4 + (0.579/2) = 5.6895 A = 0.9*0.9 = 0.81m^2 R = pgyA = 1000*9.81*0.81*5.6895 =...

Please can you help with a question I am struggling with. I have done as much working out as I could until I was completely stumped: Calculate the concrete volume that is required to keep the sluice gate AB closed, assuming that the only resisting force is the friction between the concrete...

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