Recent content by jimhebert

Thank you for resolving this problem. As you said the chart gives you the answer automatically if you know how to interpret it correctly. That's all I guess and have a good day.

I want to attach another device to the pump and it requires a certain psi to function properly.

I bought this pump in pet shop and they had one in use in an aquarium. I do want to use it in a large tank. I would still like to know the approximate PSI output curve if possible. The posted curve is not plotted correctly. The column with all the Syncras needs to be lifted up 2 increments...

I didn't notice that. This is a web page that says 3.5 HP and I also have the actual pump. http://www.petsuppliesnow.com/products/SICCE-SYNCRA-3.5-HP-PUMP-660GP.html I'll call the company to find out what is going on.

In the calculator I entered q=687, and h=12.15 and shaft bph =3.52

You mean it is not a 3.5 HP pump as the specifications say? According to your calculations, you believe it to be a 3 HP...Correct?

These specs may help in your calculations. The pump is a 3.5 horsepower. The watts are 68, voltage =120, amps=.7 The Q max GPH = 687 gph The Q min GPH = 449 gph Head max =12.5 feet

The 396 gall/hr is the flow rate with the 6 feet of head according to the chart that you are mentioning. So I guess it is still not possible to calculate the psi?

Ok, I thought maybe there was a simple formula that could be applied. Thank You anyway. On second thought, the piping is the same size as the outlet and it is only about 6 feet long, but the pump will be pumping the water up. It's for an aquarium.

I have a pump that puts out 396 gal/hr of water. The output pipe on the pump is 9/16 inch in diameter. Is there a way to calculate the psi?

Appreciate it, Michael. We'll give a try.

OK, now I've got to find the supports that will keep the tank from rupturing due to pressure. Thanks for the help.

We know that the force per square inch on the wall will increase as we go from top to bottom. Also, if my logic is correct, the force per square inch should be the same along a horizontal line drawn across the wall. With this information that we have previously calculated, how do we now...

Is it correct to say that the total force acting on the upper rectangular section of one of the 16' walls that is 2' from the top would be 62.42 x 16 x 2 squared divided by 2 = 1997 lb ?

No, I haven’t calculated the total weight on the floor. The way to do that would have been 16x4x3.5 = 224 cu.ft. Then 224x62.22 lb/cu.ft = 13,937 lbs. Total Therefore, 13937 divided by the area of the floor (64) =218 lb/sq ft. So based on the last part of your explanation, the...