A light unstressed spring has length d. Two identical particles, each with charge q, are connected to the opposite ends of the spring. The particles are held stationary a distance d apart and then released at the same time. The system then oscillates on a horizontal frictionless table. The...
i assumed that the 25% and 12% mixtures were sold at cost, so i used
.25x + .75y = 18
and
.12x + .88y = 10
solved for x and y, then substituted into .17x + .83y = z
found z, multiplied by 1.1
hopefully that's what they're looking for
A paint mixture containing 25.0% pigment and the balance water sells for $18.00/kg, and a mixture containing 12.0% pigment sells for $10.00/kg. If a paint retailer produces a blend containing 17.0% pigment, for how much ($/kg) should it be sold to yield a 10% profit?
Am I wrong, or are they...
A long coaxial cable consists of an inner cylindrical conductor with radius a and an outer cylindrical shell of inner radius b and outer radius c. The cylindrical shell is mounted on insulating supports and has no net charge. The inner cylinder has a uniform positive charge per unit length...
i figured it out earlier today
F = ma
qE = ma
\frac{eE}{m}= a
find a, use it to find the displacement (x) in the simple mechanics equation
\frac{-v_{0}^2}{2a}= x
then use x to find t :
\sqrt{\frac{2x}{a}}= t
now simply use:
\Delta KE = \frac{1}{2}mv_{0}^2 -...
another hint - the electrical field outside a spherical shell of charge with radius r and charge q is directed radially and has magnitude
E = \frac{q}{4\pi \epsilon_{0}r^2}
use a gaussian surface and take advantage of its symmetry, but make sure your point P is on the GS or else there will be error.
\Phi = \oint E \cdot dA
E will be constant, so it can be taken out of the integration, etc.
The viewing window in a diving suit has an area of 65 cm^2. If an attempt were made to maintain the pressure on the inside of the suit of 1 atm, what force would the window have to withstand if the diver descended to a depth of 150 m. Take the specific gravity of the water to be 1.05.
So...