Recent content by Jimmeh

Anyone? The exam's tomorrow, I'd just like a quick verification... Thanks

Homework Statement Homework Equations l = 0.02 m r = 0.3 m E = \frac{-d\phi}{dt} \phi = BA The Attempt at a Solution A = \pi 0.32^2 - \pi 0.3^2 = 0.0124\pi ...Area "cut" by conductor \phi = 1.5a_r0.0124\pi = 0.0186\pi a_r ...change in flux in one revolution 1600...

Ok, here're my calculations: Frequencies: cos(2t) is 1 when t=0, and is next 1 when t=\pi , therefore T_{V1}=\pi, and thus f_{V1}=\frac{1}{\pi}. \sqrt{2}cos(2t=0.25\p) is also 1 when t=0 and next 1 when t=\pi, therefore T_{V2}=\pi , and thus f_{V2}=\frac{1}{\pi} and f_{V1}=f_{V2}...

Hey, I'll post my calculations soon, but one question first: when I have the total impedance for the circuit, Z, and I want to get the total current in the circuit, I, by using Ohm's Law, I=V/Z, what form should V be in? Do I leave it as cos(2t) or \sqrt{2}\cos(2t-0.25\pi), or do I have to...

Yup, I had to google superposition, but yeah, that's what I'm doing. By short circuit, do you mean redraw the circuit with a wire in place of the voltage source you're ignoring at the time? If so, that's what I was doing, yeah.

That's what I thought I was doing, but how do you get the voltage at the node above the capacitor? What I thought you had to do was get the voltage at the node due to V1 (V1 - voltage drop across the resistor and 0.5H inductor due to V1) and then get the voltage at the node due to V2(V2 -...

What steps would you take exactly to do it as a "straightforward sum"? I'm unsure what you mean by doing the question with KCL, as in just verify that the currents I get are consistent with one another?

My answer is wrong, I've just realized I made a big mistake. But by "ignoring V2", I meant I calculate the voltage across the capacitor as a result of V1 and then ignore V1 and calculate the voltage across the capacitor as a result of V2, and then add them both together to get the total voltage...

Homework Statement Homework Equations My answer: I_C=(\frac{1}{6}-\frac{1}{2j})(cos(2t)+\sqrt{2}cos(2t-0.25\pi)) THIS IS WRONG.The Attempt at a Solution The way I went about doing this was: 1. Ignored V2 and worked out the total impedance in the circuit for V1. 2. Calculated the voltage...