Recent content by Jimsac

Thanks so much Sirus! After reveiwing your equation a couple of times I got it.

ok so i know that my intial pressure is room temperature 20degress C It has a pressure of p1. It is increased to 1.5p1. Do I take the work done by the system + the internal work?

does this look right? (200g)(540) + (200g)(.50)(110degreesC-0degressC) (108kg) + (11)= 119kg Is this the problem from steam to ice? Do I have to now bring it to another phase?

I have to change steam at 110C and end up with water frozen into ice at 0.c . How much heat will be removed? How do I go about changing this to steam, liquid, solid? Do I use mLf+mcdeltaT each time?

p NT V

Not sure what formula to use to solve this problem A cylinder of gas at room temperature has a pressure of p1. To what temperature in degrees C would the termperature have to be increased for the pressure to be 1.5p1? Thank you all for your help

Not understanding a formula for this problem Which has more kinectic energy a .00020-kg bullet traveling at 400m/s or a 6.4 10 to 7th power -kg ocean liner traveling at 10m/s (20 knots)? I know that w=fd=mad=ma(1/2)at2) =1/2m(at)2 +1/2mv2 Is this the right formula?

misunderstood What I do not understand is what to do with the formula. How do you solve this problem? THis is just an example in the book with the answer given but I do not understand what to do with the formula to solve it. Sorry

I know the formula I do not understand how to solve it

Here is the ex. in the book. Two 3.kg textbooks are .15 apart. What is the gravitational attraction? The answer is given 2.7*10-8 I also know the formula is F=Gm1m2/r I just do not understand what they are doing to get the answer. (6.67*10-11 N-m2kg2)(3.kg)(3.kg)/.15 This is the...