Recent content by jjf5122

Homework Statement A bicycle weighs 23lbf, including hollow wheels each weighing 2.5lbf. Calculate how much of the bike's kinetic energy is in the wheels. Ans = 36%Homework Equations 1. I = mr^2 <----- i think this is 2mr^2 because of two wheels 2. Kinetic Energy = 1/2mv^2 <---- translational...

ok now i understand everything u said and i know how to do it now. And i would like to add that this website is the most help i have ever received from any source. I've gone to study sessions at the math lounge at my college and sought help from other students in my class and this site...

vf/vi=1/sqrt(2) is what i should actually be using? What am i solving for in this equation...and the answer specifically states that they are both .707, one isn't negative.

ok well, the answer is actually given...i just need to know how it is solved, the answer that it gives is: .707m/s, .707m/s

Homework Statement Two identical objects, each moving at 1m/s but in oposite directions collide partially inelastically in one dimension. Assume the final total kinetic energy is half the intial total value. Calculate the final speed of each object Homework Equations This is my...

hmm...so i don't actually have to plug a mass(inthe denominator) or 9.8 m/s^2 into the formula?

2m(9/16)/mg( this is where I am confused...g would be 9.8m/s^2?) if i multiply 4m(9.8) i get 39.2 m^2s^2 none of this seems to reduce down to the answer in my book of 9/32 v0^2/g

Sry this is frustrating for me...wouldnt the velocity i solved for actually be the initial velocity, right after the collosion occured, and the final velocity be 0(because it will come to a stop briefly when it reaches its max height)? So I am still confused as to how this is actually set up...

Yes but I am confused as to how to actually set this up to work...how do i use the velocity that i got, or do i need to. Am i suppossed to use, delta K + delta Ug(ptoential gravitational force) = 0? And if so...how would i actually set this up? also... K= mgh U = -mgh

awesome i see what u mean. The momentum of the first object is 0 because its at rest. the total mass is obviously 4m therefore: 3m vo/ 4m... the ms cancel leaving 3/4 vo. Ok i get that now. However... what is the conservation of energy formula that i need to solve for the distance?

hmm...how do i do that if no actual masses or velocities are given? v'= m1v1+m2v2/ total mass...but i have no numbers, am i missing something?

the book i was given for this class shows barely anything at all in it. I don't really know where to begin. The only equation given in this entire chapter relating to a inelastic equation (which I am assuming this collision is) would be>>>>>> m1v1+m2v2=(m1+m2)v' however...where...

Question: A ball of mass m is suspended from a string of length l. A lump of clay of mass 3m is thrown horizontally at the ball w/ a speed of v0 making a direct hit and sticking to it. Find the speed of the combined object right after the collision, and how high it rises. Answer: 3/4vo...