Recent content by jlmessick88

so basically that means... c^2 = a^2 + b^2 = 7 (7*10)(.05)cos(1) = 2.5??

http://i63.photobucket.com/albums/h148/jlmessick88/Image.jpg here's a pic that should work... i'm not sure if what you're talking about is exactly what's going on...if it is then i might need you to explain a bit more :)

oh wow...i didn't know i could do that...thanks!

here is an image of my ray tracing

how could they converge on the same side of the lens as the object if i draw the ray through the near focal point (which is behind the image itself) the ray would be pointed downward... the two other rays, if drawn in the same direction (behind the image) they don't converge

any ideas? anyone??

well the focal point is behind the object... then when drawing the ray parallel to the axis, the special ray will refract through the far focal point... the ray through the center of the lens, the ray does not bend, just continues through the lens at a straight line... these two lines never...

Homework Statement An object is 6.0 cm in front of a converging lens with a focal length of 10 cm. Use ray tracing to determine the location of the image. Is the image upright or inverted? Is it real or virtual? The Attempt at a Solution According to my ray tracing...there is no...

here's a picture

Homework Statement A 10 cm x 10 cm square is bent at a 90° angle . A uniform 0.050 T magnetic field points downward at a 45° angle. What is the magnetic flux through the loop? Homework Equations Φ = AB cos θ Φ = (pi * r^2)B cos θ The Attempt at a Solution b = .050 T cosθ =...

i guess I'm still not getting it...everything that i read shows that the electric field and the mag. field are always perpendicular...all of my answers indicate that they are opposite from each other...how??

so with that in mind, the electric field would be directed out the plane of the paper?

Homework Statement Assuming the particle in Figure P24.62 is positively charged, what are the directions of the forces due to the electric field and to the magnetic field? a. The force due to the electric field is directed up (toward the top of the page); the force due to the magnetic field...

my book says that the Earth's magnetic field strenght is 5 *10^-5...so would i use that instead of the .4 x 10^-4??

using Ampere's law the magnetic field ina solenoid will be given by B= magnetic permeability x current i x number of turns N / length L and for cancelling Earth's magnetic field, the current needed is i = B x L / N x magnetic permeability = 0.4x10^-4 x 4 / 5000x 4 pi x 10^-7 = 2.55...