Recent content by jmiersy

Thanks! And yes I will show the working more clearly. And I also understand how the torque will vary along the shaft. Thanks again for your time.

ok i think i now understand. Your bluntness is appreciated haha. I worked the question with both values and now see how designing to 80/1.5 delivers a greater diameter. I've attached the working if you could look over it and see if i have done the correct thing? thanks for your time once...

or am i thinking about this in the wrong way?

"calculate a suitable diameter to the nearest millimetre for the secondary drive shaft for a FOS of 1.5, if the shear stress in the shaft is not to exceed 80MPa when the shaft is under maximum load. (Hint – be careful about the point in your calculations where you apply the FOS. It isn’t just a...

heres the question. https://www.physicsforums.com/showthread.php?t=440448

ok well i suppose i need to be more specific to the factors of this question. It is a first year engineering question that i have been studying, i will post the details of the question for you guys to comment on. thanks for everyones time.

im working on a question that requires me to calculate the minimum shaft diameter for a maximum shear stress. the value is 80mpa. The factor of safety is 1.5, now I am aware that i can't simply increase the shaft diameter by 1.5 to do this correctly. Should I calculate a suitable diameter for...

so assuming that this is correct, i then attempted b. it asks for max torque in shaft b, max torque occurs at max power. max power occurs when 2444 rpm. 40/208 = .1923 rotations to every one of the small gear x by 2444 /60 = 7.8 rots/sec of the large gear. so p=T.2(pi).f 28.5x10^3=T.2(pi).7.833...

so I am leaning towards the idea that power is simply .95 percent of the power supplied, meaning that the angular velocity and the torque are obviously different. am i on the right track of understanding this?

p.s. thanks in advance.

Homework Statement The problem is attached, I am only looking for guidance on a, I am most probably just completely over complicating this. Homework Equations p=T.2(pi).f t= torque f=frequency/rot/sec The Attempt at a Solution im just stuck on wether the power in shaft b is...