Recent content by jodecy
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J
Find the following indefinite integral
ok so i worked it out using the subst of u = 1 - x^2 and got the answer to be -1/3 (1-x^2) ^ 3/2 + c. however the original method i used was that presented to me by my lecturer so I'm wondering ...- jodecy
- Post #5
- Forum: Calculus and Beyond Homework Help
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J
Required to prove that ∫f(x)dx[b, a] =∫f(x−c)dx [b+c, a+c]
i believe it was given in a lecture i had so i assumed is that a wrong assumption?- jodecy
- Post #3
- Forum: Calculus and Beyond Homework Help
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J
Required to prove that ∫f(x)dx[b, a] =∫f(x−c)dx [b+c, a+c]
Homework Statement required to prove that ∫()[, ] =∫(−) [+, +] where f is a real valued function integrable over the interval [a, b] Homework Equations ∫() [, ]=()−() The Attempt at a Solution ∫() [b, a]=()−() ∫(−) [+, +]=(+−)−(+−)=()−() ∴∫()[, ] =∫(−) [+, +]...- jodecy
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- Replies: 4
- Forum: Calculus and Beyond Homework Help
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J
Find the following indefinite integral
ohhhh so i need to state θ = arcsinx therefore my answer in terms of x would be -1/3 cos^3(arcsinx )? when i come back i'll try subst with u = 1-x^2- jodecy
- Post #3
- Forum: Calculus and Beyond Homework Help
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J
Find the following indefinite integral
Homework Statement find the indefinite integral of ∫x√(1-x^2) dx Homework Equations The Attempt at a Solution ∫x√(1-x^2) dx let x = sinθ dx = cosθ dθ now sin^2θ + cos^2θ = 1 => cosθ = √1-sin^2θ ( for the form √(1-x^2)) ∫x√(1-x^2) dx => ∫sinθ (√1-sin^2θ) cosθ dθ =>...- jodecy
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- Indefinite Indefinite integral Integral
- Replies: 4
- Forum: Calculus and Beyond Homework Help