Recent content by Joe brewer

Let me walk you through what I'm thinking 1.ice is added 2.water gives up heat to ice, heating it up and turning into ice (still at 0c) 3.this continues until all the ice(old and new) is at 0c 4.water is still at 0c On another note, Is this how (re) crystallization works?

Well, I was thinking somewhere between zero and the temp of the ice. Would it always be zero but the amount of ice would just increase? That's the only way I can think of that allows any water to be left over.

So it would all turn to ice no matter what?

Yep! Basically as long as the ice is below zero, equilibrium will be at an intermediate temperature and will have x amount of additional ice.

0C is when any amount of water and ice would be at equilibrium. At -5 C presumably the ice would increase in temp and some of the water would freeze.

The same thing except it would equilibrate at a higher temp (still below zero). Probably less ice formed as well. Am I on the right track here? Edit: or if there is enough ice, All of the water would turn to ice in both cases because all the water has to decrease in temperature. Since the L_f...

Well I think that the ice can't melt, but the temp must equilibrate. So the heat will flow from the water to the ice. This will form more ice and raise the temp of the new ice until equilibrium is reached. Better?

Oh so there will be more ice formed but it will equilibrate at a temp between - 20 C and 0 C. Is that right?

Homework Statement What will happen when a large amount of water at 0 C is mixed with ice at - 20 C? Assume ideal conditions. Homework Equations N/A The Attempt at a Solution I think the ice will rise in temp (without melting) but no new ice will be formed. Is this right?