Recent content by JOEandSTEPH

Thank you, Dick!

That gives us t = 2.284 milliseconds So E = 15.sin(50.pi.[2.284[SIZE="1"]x10-3]) + 40.cos(50.pi.[2.284[SIZE="1"]x10-3]) So E = 42.72

Okay I think I get what you're saying. So, 750.pi.cos(50.pi.t) - 2000.pi.sin(50.pi.t) = 0 750.pi.cos(50.pi.t) = 2000.pi.sin(50.pi.t) 750.pi = 2000.pi [sin(50.pi.t)] / cos(50.pi.t)] 750.pi = 2000.pi.tan(50.pi.t) 750.pi / 2000.pi = tan(50.pi.t) tan-1[750.pi / 2000.pi] = 50.pi.t t =...

We've been given the following equation, E = 15.sin(50.pi.t) + 40.cos(50.pi.t) We've been asked to find a value of E we think at its maximum value (can't quite remember the question at the moment). We know that the second derivative will give us whether the equation gives the maximum or...

1. For a school project we're building an emergency braking system. In addition, we also want to trigger an audio-visual alarm system to alert a third party to the operation of the system. For the alarm system we are using a 555 timer to generate a squarewave output to alternate a buzzer between...