Maximum value of E = a.sin(x) + b.cos(x)

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Homework Help Overview

The discussion revolves around finding the maximum value of the equation E = 15.sin(50.pi.t) + 40.cos(50.pi.t). Participants are exploring methods to differentiate the equation and solve for the variable t to determine the maximum value of E.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to differentiate the equation and set the derivative to zero to find critical points. They express confusion about isolating t in the resulting equation. Some participants suggest using trigonometric identities and manipulating the equation to find t without taking the inverse cosine.

Discussion Status

Participants are actively engaging with the problem, offering alternative approaches to isolate t. There is a progression in the reasoning as they refine their methods, but no consensus has been reached on the final value of E.

Contextual Notes

There is an indication of confusion regarding the manipulation of trigonometric functions and the implications of the second derivative in determining maximum values. The original poster also notes uncertainty about the exact requirements of the problem.

JOEandSTEPH
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We've been given the following equation,

E = 15.sin(50.pi.t) + 40.cos(50.pi.t)

We've been asked to find a value of E we think at its maximum value (can't quite remember the question at the moment). We know that the second derivative will give us whether the equation gives the maximum or minimum value (think it's giving us the maximum anyway) so we're sure that we are just required to differentiate it once, equal it to zero to find a value for t and then put the value of t back into the original equation.

dE/dt = 750.pi.cos(50.pi.t) - 2000.pi.sin(50.pi.t)

The problem is when we transpose the equation because we get really confused. This is as far as we've got:

750.pi.cos(50.pi.t) - 2000.pi.sin(50.pi.t) = 0
750.pi.cos(50.pi.t) = 2000.pi.sin(50.pi.t)
cos(50.pi.t) = [2000.pi.sin(50.pi.t)] / 750.pi
50.pi.t = cos-1([2000.pi.sin(50.pi.t)] / 750.pi)
t = [cos-1([2000.pi.sin(50.pi.t)] / 750.pi)] / 50.pi

Okay, so now what happens? There is still a t on the right side of the equation and we don't know how you can get it over to the other side to get t to the 2 and then square root the right side.

Any ideas? Are we way off? Any help would be greatly appreciated.

Thanks.
 
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You don't want to take cos-1. Divide both sides of your equation by cos(50.pi.t) and remember sin/cos=tan.
 
Okay I think I get what you're saying.

So,

750.pi.cos(50.pi.t) - 2000.pi.sin(50.pi.t) = 0
750.pi.cos(50.pi.t) = 2000.pi.sin(50.pi.t)
750.pi = 2000.pi [sin(50.pi.t)] / cos(50.pi.t)]
750.pi = 2000.pi.tan(50.pi.t)
750.pi / 2000.pi = tan(50.pi.t)
tan-1[750.pi / 2000.pi] = 50.pi.t

t = (tan-1[750.pi / 2000.pi] / 50.pi
 
JOEandSTEPH said:
Okay I think I get what you're saying.

So,

750.pi.cos(50.pi.t) - 2000.pi.sin(50.pi.t) = 0
750.pi.cos(50.pi.t) = 2000.pi.sin(50.pi.t)
750.pi = 2000.pi [sin(50.pi.t)] / cos(50.pi.t)]
750.pi = 2000.pi.tan(50.pi.t)
750.pi / 2000.pi = tan(50.pi.t)
tan-1[750.pi / 2000.pi] = 50.pi.t

t = (tan-1[750.pi / 2000.pi] / 50.pi

Yes. That's the right way to solve an equation like that for t.
 
That gives us t = 2.284 milliseconds

So E = 15.sin(50.pi.[2.284x10-3]) + 40.cos(50.pi.[2.284x10-3])

So E = 42.72
 
Thank you, Dick!
 

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