Recent content by John3509

  1. J

    Calculating the sum of a series of cubes

    Besides the equations you got for table 1 and 2, I don't get any of this. Isn't mcastillo356s method the "proper" method to solve these types of things dealing with sequences and series, the way presented to students?
  2. J

    Calculating the sum of a series of cubes

    Why wouldn't we be able to? We get the expression in ImCheetos reply. Is there something im missing?
  3. J

    Calculating the sum of a series of cubes

    Not really. ((.5)x2+(.5)x)2 Is all I got. But that requires having that equation already, which I still don't get how the book expects you to figure that out, because the way I did certainly isn't it. And while I know what summation notation it is hasn't been covered in the book yet eighter.
  4. J

    Calculating the sum of a series of cubes

    Mentor note: Moved from technical math section, so missing the homework template filling in the boxes is easy, 1,3,6,10,15 second is just squares of that, 1,9,36,100,225 But how I anyone supposed to find and expression for this? This is from a textbook on elementary algebra, the specific...
  5. J

    Confused about kinematic equations

    These are some nice visual aids, what program did you use to make them? My visualization for why v average can be used is a bit different tho.
  6. J

    Confused about kinematic equations

    Can someone translate this?
  7. J

    Confused about kinematic equations

    Ok now that makes sense intuitively, but ironically now the arithmetic doesn't make sense to me you can only use vav because in a parabola a line from the origin to some point @ (t) is only parallel to a secant line in between the origin and (t). My original set up would only use the velocity...
  8. J

    Confused about kinematic equations

    x=x0=vt v=v0+at x=x0+v0t+(1/2)at2 That (1/2) there does not make sense to me. It makes sense mathematically, if you integrate the velocity formula you get the (1/2) as a result of the integration rules and if you differentiate its needed to cancel out the 2 and arrive at the velocity...
  9. J

    Switching reference frames between two intersecting lines

    Yea im good, thanks. I always thought that's one and the same, all motion is relative after all. I don't understand half of what you said, but I guess that's because I'm not there yet. So like alf staying in place and the starting line moving back. Interesting, I dont even know how to begin...
  10. J

    Switching reference frames between two intersecting lines

    Oh I got it, 1320/60 is 22 as well, I saw the different y intercepts and panicked I forgot in this reference frame there is no +2. Anyway, whats the difference between translating and changing reference frames?
  11. J

    Switching reference frames between two intersecting lines

    I wasn't aware there is a difference between translating and changing reference frames, what is the difference? It took me like 45 minutes to make those graphs in paint with my mouse. I dont see the utility in making a to scale graphs when these are sufficient to to demonstrate the concept at...
  12. J

    Switching reference frames between two intersecting lines

    The graphs are not to scale, just meant to show in general the concept. Im assuming you are referring to the first graph since I posted 4 of them? And the graph shows that at T=0 alf is 2(660) meters ahed, as claimed in the problem statement. They are just lines, they can go on forever, im sure...
  13. J

    Switching reference frames between two intersecting lines

    I got no problem with the arithmetic and solving it, finding the intersection of 2 lines is nothing, but I decided to play around with the problem and explore it more and ran into a strange problem, why can't I shift the X axis up? Let me explain. The problem can be set up from 2 different...
  14. J

    B Understanding Horner's Method: A Brief Explanation for Confusion

    [SIZE=16px][FONT=noto sans] But that's just the [SIZE=16px][FONT=noto sans]polynomial remainder theorem[SIZE=16px][FONT=noto sans] , which involves polynomial division, horners method just reformats a polynomial into a nest of linear terms. In that section it says "[SIZE=16px][FONT=noto...
  15. J

    B Understanding Horner's Method: A Brief Explanation for Confusion

    I know what synthetic division is and what its point is, its an algorithm that allows you to do polynomial division in a more compact way, by not having to write the variable and its powers. Its how it relates to Horner's method, the reformatting a polynomial into a recursive nest of linier...
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