Recent content by John982

our real depth then is 2/Tan32.1=3.19 m. Thank you so much for your help.

So could I do the same thing to find x by subtracting 45° from 90° which is 45° and if the length of the apparent depth is 2 meters then x must also be 2 because 45-45-90 triangles have legs of equal length?

The horizontal side x does not change. Could you find the angle by subtracting θ2 from 90° which would make ϕ 58°?

Then based on that it would be: sinθ2= (1.00/1.33)(sin45) -> θ2=32.1°. Now that I have the angle I can use tanθ=opp/adj correct? But how do I know what the opposite side length is?

Robert is on a ship looking at a school of fish below the lake surface. He estimates the apparent depth of the school to be two meters, and that his observation angle is forty five degrees. Calculate the real depth of the school. Here is what I think we know: θr=45°, θi=?, ni=1.00, nr=1.33...

I knew it was just me forgetting a geometry rule. Thank you for your help.

This isn't even a homework question but in my textbook there is an example on how to find the angle of deviation in a prism. I understand how they got all the angles listed in the picture but what I cannot understand is how the angle of deviation can be found from 70 - 12 = 58 degrees (answer in...