Recent content by johnq1

You can find an answer only using p^2 = a^3/M (with M expressed in solar masses) so would it be... M= .158/2.075 M= .076144578313253 AU .076144578313253(2*10^30) = 1.52289157 × 10^29kg That's off by over 37% so that doesn't seem right.

The mass of the Juipter moon Sinope is 8*10^16 but I looked that up, didn't figure it from what was given.

Homework Statement Using a modified version of Kepler's third law and data about Sinope calculate the mass of Jupiter. Keplers Third Law: p^2=a^3 Newton's Version: p^2=a^3 / M + M p^2 = a^3/M M=a^3/p^2 Sinope's period of orbit = 2.075 years Average orbital distance of Sinope is 0.158...