Recent content by jokiemay
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J
Proving the Solution to a Recurrence Relation Using Mathematical Induction
Thanks all. Ive to change T(1) = 1 to T(1)=0 and re write the equation.- jokiemay
- Post #13
- Forum: Precalculus Mathematics Homework Help
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J
Proving the Solution to a Recurrence Relation Using Mathematical Induction
Base S(1)=1, so T(1)=S(1) for some n, T(n)=S(n), then: T(n+1) = 2T(n)+2 = 2(3×2^(n-1) -2) +2 = 3 × 2^n-4+2 = 3×2^n-2 = S(n+1) Proof that T(n)=S(n) then T(n+1)=S(n+1), and as we have T(1)=S(1) i have proven by induction that T(n)=S(n) for any n in the positive integers- jokiemay
- Post #10
- Forum: Precalculus Mathematics Homework Help
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J
Proving the Solution to a Recurrence Relation Using Mathematical Induction
cheers for your help, @ mark, the layout that the coursework has been set is confusing me. I am emailing my leacturer to enquire about the questiion.- jokiemay
- Post #8
- Forum: Precalculus Mathematics Homework Help
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J
Proving the Solution to a Recurrence Relation Using Mathematical Induction
sorry its T2=1 / 2 = 1 the confusing part is why Sn is related to Tn , I am just going to base it on Tn. The statement n > 1 is true and by the replys i seem to have gone very wrong somewhere?- jokiemay
- Post #5
- Forum: Precalculus Mathematics Homework Help
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J
Proving the Solution to a Recurrence Relation Using Mathematical Induction
Hi all, I've been struggling with a large piece of coursework. been quite stressed latley and now I am struggling while aproaching my deadline. i need help answering this question. Use mathematical induction to show that S(n) = 3 × 2 n-1 -2 is the solution for the recurrence relation: T(n)...- jokiemay
- Thread
- Induction Mathematical Mathematical induction
- Replies: 13
- Forum: Precalculus Mathematics Homework Help
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My calculations - youngs modulus
can anybody shine light on this ?- jokiemay
- Post #4
- Forum: Introductory Physics Homework Help
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My calculations - youngs modulus
ive edited the post above . thanks- jokiemay
- Post #3
- Forum: Introductory Physics Homework Help
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My calculations - youngs modulus
Im about to hand coursework in. Its the youngs modulus of copper wire We added 100g weights and measured the extension using a traveling microscope. for example at 0.900kg the wire extended by 6.36cm my calculations are Diameter = d 2.7x10-5 m Cross section area A = Pi x d...- jokiemay
- Thread
- Calculations Modulus
- Replies: 3
- Forum: Introductory Physics Homework Help
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Ive to work out the uncertainties for youngs modulus.would i take
basically my stress and strain are A = 5.73 x 10-3 L = 1.788m F = 8.829 kg m s-1 e = 6.36cm or 6.36x10-1m youngs modulus is 6.02x10(10) Pa ive to find the % uncertainty in the Young Modulus value- jokiemay
- Post #2
- Forum: Introductory Physics Homework Help
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Ive to work out the uncertainties for youngs modulus.would i take
Ive to work out the uncertainties for youngs modulus. would i take all 4 measurements and mutliply then divide by 4 ? would 1.788m have an uncertain if +/- 0.01 ? how would i get the uncertainties from 5.73x10-3 im very confused and my tutor isn't helpful at all.- jokiemay
- Thread
- Uncertainties Work
- Replies: 1
- Forum: Introductory Physics Homework Help
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Youngs Modulus of copper wire experiment
Hi there - My mistake was the diameter - it should have been calculated as 0.000573mm or 5.73x10-3 so the result in getting now is 6.03 x 10(10) Pa as the youngs modulus. Im also working out the percentage error; ive worked out the length as 1.788m +/- 0.01m so 0.01/1.788 x 100 = +/- 0.56%...- jokiemay
- Post #12
- Forum: Introductory Physics Homework Help
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Youngs Modulus of copper wire experiment
can anybody else hint to me where I am going wrong as i see Cu is suppost to be 117GPa- jokiemay
- Post #10
- Forum: Introductory Physics Homework Help
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Youngs Modulus of copper wire experiment
Yes the 0.27 is the diameter which is the cross sectional area (A) I calculated that as Pi x 0.27squared / 4 Thanks very much for your help so far.- jokiemay
- Post #9
- Forum: Introductory Physics Homework Help
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Youngs Modulus of copper wire experiment
so would be answer of 68077.97019246913753978559011651 be right ?- jokiemay
- Post #7
- Forum: Introductory Physics Homework Help
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Youngs Modulus of copper wire experiment
im getting 68077.97019246913753978559011651 couldnt be right- jokiemay
- Post #5
- Forum: Introductory Physics Homework Help