1/2 lambda or 1/2 wave length is the distance between two succesive nodes or anti-nodes(crests).
so your textbooks shows
1 full wave length + 1/4 of a wave length
so 1 + 1/4 = 5/4 wave length ( or 5/4 lambda)
so it is correct.
your teacher's diagram;
1 full wave length + 3/4...
MANY WAYS TO DO THIS.you can write it as a exponent.
z^4 + 7 -24i = 0
z^4 = - 7 +24i
Z = Cos(2*n*pi+ theta) + i Sin(2*n*pi + theta) = exponent(i*(theta+2*n*pi))
n = 0, 1,2,3,
so
Z^4 = exponent(i*(theta+2*n*pi)*4)
= Cos((theta+2*n*pi)*4) + i Sin((theta+2*n*pi)*4) (De Moivre's...
it got to do with the centrifugal force and the gravitational force. i.e. if an object goes in a circle, there is a pseudo force called centrifugal force that tries to push it away. for ex. if you attach a piece of string string to a stone and swing it, it will start going in a circle. if you...
this is a 3D problem. since your wires have finite lenghts, you need to have all three coordinates (x,y,z dependence) in your general solution.
Once you have the general solution, then apply necessary conditions to get the field at the point you need.
it will be easier if u use cylindrical...
i don't know for sure.
momentum is
grams*meter/second
r u sure u got his right?
if so, if such quantity exists,
it would be decribing the flow rate or something similar. (this is purely based on your units).
it is hard to visualize these things. all these are part of theoritical models to decribe experimental observations. as long as they fit the model and we are able to explain the experimental observations, no body cares. u just have to believe it for a while, until u study things in deep. but...
all u need is
(v)^2 = (Vo)^2 + 2(a)(delta X)
the point here is, to think what happens when u hit brakes. u slow down, which is a deceleration or a negative acceleration. (opposite is speeding up, which is positive acceleration). usually in a problem like this both these situation are...
V=at+Vo ---------------(A)
X=1/2at^2+Vot+Xo -----------(B)
ok. couple of things to note
assume we are measuring height from ground. (i.e. X0 = 0)
at maximum height, the velocity of the ball becomes zero for a moment just before it turns around. so at the point V = 0
so equation (A)...