Hi.
Lets say I have two batteries{each one has a 12 volts} connected in parallel circuit with a load of 2 ohms.This means,that each battery will force a current of 6A through the circuit and we will have 12 amperes through the circuit.
Is this correct.Does the total amount of amps in the...
I understand the "1/r2" part of the equation.The inverse square law is easy to understand.I have problem with the q1q2 part of coulomb's law,but I guess it experimental thing.
I don't understand one thing.Charles Coulomb was probably sure of his law because Coulomb had the torsion balance.But...
Hi Tiny Tim.I'm afraid I don't understanding.If I replace one of the charges with ten more I know that the force would be 10 times bigger.But that, the formula says.But I want to have some intuitive understanding of this.
Other man told me that Coulomb law is a direct consequence of Maxwells...
Hi.I want to know why we multiply the separate charges in the coulomb equation.I understand that the force is proportional to the charges, but I don't understand why we multiply charges.Why just we don't add them together.Are there any theoretical explanation for this.The same goes for the...
Hi tiny-tim.Thank you very much for your help.I think I understand now what is going on inside a capacitor.If you want, please tell me if my reasoning is now correct.
I still think that if we have more charge on a plate A the voltage would be bigger, but in this case because of the coulomb...
If we increase the battery voltage,we will increase the capacitance too.If this is correct then,increasing the capacitance by moving the plates more close should increase the voltage.
Hi tiny-tim.Thanks for your answer but I still don't understand the problem.
I am considering only the charges of one plate.For example, if we take the negative plate,the negative plate will accumulate charge until the voltage across the capacitor is equal to that of the battery.Now if we bring...
I need help with something.I have problem to understand how the capacitance of a capacitor can be increased if we move the plates of the capacitor more close.
Here's my reasoning:
The capacitor is just a extended terminal of a battery,so the battery voltage must equal the capacitor...