Recent content by jonathanlv7

Finally! I got! Its arcsine(sin(phi-arcsine(1/n))) = 11.64 --- Thanks for helping me out! I have some other problems I'm going to start on so if you don't mind sticking around the forums for a little that'd be awesome!

So I worked on it some more and I got this answer - AngleOfIncident is 90 degrees. Is this right? For part A

I got the equation from http://imgur.com/KdlNuLH --- Also, I figured out part B so that's done. TY for helping! EDIT: I don't think that angle i called 90 degrees is actually 90 degrees

Yeah I'm looking at it and I can't see how to relate the critical angle to the angle I want. Something I tried which I think is wrong is AngleOfIncident = arcsine(nsin(90-arcsine(1/n)))

Homework Statement Suppose the isosceles prism of the figure(http://imgur.com/EQiQSoO) has apex angle φ = 53.4° and index of refraction n = 1.41. (a) What is the smallest angle of incidence θ for which a ray can enter the left face of the prism and exit the right face? (b) What angle of...

Homework Statement Two identical long wires of radius a = 2.90 mm are parallel and carry identical currents of i = 5.00 A in opposite directions. Their center-to-center separation is W = 17.0 cm. Neglect the flux within the wires but consider the flux in the region between the wires. What is...

Figure (a) shows a narrow charged solid cylinder that is coaxial with a larger charged cylindrical shell. Both are nonconducting and thin and have uniform surface charge densities on their outer surfaces. Figure (b) gives the radial component E of the electric field versus radial distance r from...

Accel. in x is 0 accel. in y is -g. vel. in x is whatever the initial velocity in the x direction was. vel. in y is -gt + whatever the initial velocity in the y direction was. pos in x is whatever the initial velocity in the x direction was times t. pos in y is -g/2t^2 + t times whatever the...

Okay so I'll try to write out everything I did here with slashes and ^. So accel. equals <0,-g> then I integrate to get vel. = <sqrt2/2*magnitude of the initial velocity,sqrt2/2*magnitude of the initial velocity - gt> integrate again to get pos = <(sqrt2*t)/2*magnitude of the initial velocity...

Here are pictures of my work:http://i.imgur.com/JwVipFV.jpg http://imgur.com/qkqyf6h

So I get why this is the answer, but I really want to know why what I did didn't work. I'm going to upload a picture of my work and maybe somebody can point out the error.

Yeah I know it's not right. I just don't get what I did wrong.

19.78 m/s

I got that the initial speed in the x and y direction is 277.5394, which is apparently wrong. Although the y speed is getting continuously lower since the acceleration is -g. X velocity stays constant at 277.5394.

Homework Statement A stone is thrown horizontally from the top of a 20-m high hill. It strikes the ground at an angle of 45◦ . With what speed was it thrown? Homework Equations g=9.8 projectile motion is symmetric The Attempt at a Solution I got the answer 277.539 by treating this is a...