Recent content by Jonsson

  1. J

    A Why Orbital Time is 6πGM in Schwarzschild Geometry

    Distance over the speed: ##\Delta \tau = \frac{2 \pi r}{c} = 6 \pi GM ## I exected it to work if you replace ##\Delta t \to \Delta \tau##, but not this way around.
  2. J

    A Why Orbital Time is 6πGM in Schwarzschild Geometry

    Hello there, We know that for lightlike paths, there are circular geodesics at ##r = 3GM## in Schwarzschild geometry. Suppose an observer flashes his flashlight at ##r=3GM## and after some time the light reappears from the other side of the black hole. The time he measures is ##6 \pi GM##. I...
  3. J

    A Evaluate Covariant Derivative on Tensors

    Great, I don't know. I am trying to understand how this all works. Would you like to explain some more?
  4. J

    A Evaluate Covariant Derivative on Tensors

    Hello there, Recently I encountered a type of covariant derivative problem that I never before encountered: $$ \nabla_\mu (k^\sigma \partial_\sigma l_\nu) $$ My goal: to evaluate this term According to Carroll, the covariant derivative statisfies ##\nabla_\mu ({T^\lambda}_{\lambda \rho}) =...
  5. J

    A GR index gymnastics -- Have I misunderstood something or typo?

    No, then I wouldn't have needed to ask. Thank you for your help :)
  6. J

    A GR index gymnastics -- Have I misunderstood something or typo?

    Carroll -- Spacetime and geometry. Page 333
  7. J

    A GR index gymnastics -- Have I misunderstood something or typo?

    This is in the context of deriving the Friedmann equations, so surely we are using comoving coordinates?
  8. J

    A GR index gymnastics -- Have I misunderstood something or typo?

    Inertial coordinates are free fall coordinates, the coordinates of a freely falling observer? This is in the context of deriblant the Friedmann equations, so surely means comoving coordinates?
  9. J

    A GR index gymnastics -- Have I misunderstood something or typo?

    $$ T^{\mu \nu} = g^{\mu \rho}g^{\nu \sigma} T_{\rho \sigma} = g^{\mu \rho}g^{\nu \sigma}\left[(\rho + p)U_\rho U_\sigma + pg_{\rho \sigma} \right] = (\rho + p)U^\mu U^\nu + p g^{\mu \nu} = \begin{bmatrix} \rho + p &0&0&0\\ 0&0&0&0\\ 0&0&0&0\\ 0&0&0&0 \end{bmatrix}^{\mu \nu} + \begin{bmatrix} -p...
  10. J

    A GR index gymnastics -- Have I misunderstood something or typo?

    Hello there, I am learning GR and in the cosmology chapter, we are using the metric $$ ds^2 = - dt^2 + a^2(t) \left[ \frac{dr^2}{1 - \kappa r^2} + r^2 d \Omega \right]. $$ Suppose now that ##U^\mu = (1,0,0,0)## and the energy momentum tensor is $$ T_{\mu \nu} = (\rho + p)U_\mu U_\nu + p g_{\mu...
  11. J

    Solution strategy for linearized gravity problem

    Thanks. I found the deflection angle is ##\frac{4GM}{b}##. How do you say I transform this quantity back?
  12. J

    Solution strategy for linearized gravity problem

    That is a good thing, because we are not interested in all null paths. Yes, I agree these solve (*), but why is it important that you've found exactly one solution that don't interest us? Can you propose some strategy that will work?
  13. J

    Solution strategy for linearized gravity problem

    I added a drawing to my previous post. There are three sets of coordinates. (1) ##(t,x,y,z)## as I have drawn in the picture above (2) ##(t,x^1,x^2,x^3)## where the mass is stationary (3) ## (t,\zeta^1,\zeta^2,\zeta^3) ## where the mass is moving. It may well be that ##(t,x,y,z) =...
  14. J

    Solution strategy for linearized gravity problem

    Ok, I have been working away at this. I found the metric in the non moving frame. But how do I go from there. Suppose I write the up the geodesic equation or equations for conservation of momentum along a geodesic $$ 0 = g_{\mu \nu} \frac{dx^\mu}{d\lambda}\frac{dx^\nu}{d\lambda}, $$ We don't...
  15. J

    Solution strategy for linearized gravity problem

    Alright, I take it then that $$ \frac{\partial x^\mu}{\partial x^{\alpha'}}\frac{\partial x^\nu}{\partial x^{\beta'}}g_{\mu \nu} = \Lambda^\mu_{\alpha'}\Lambda^\nu_{\beta'}(\eta_{\mu\nu}+ h_{\mu\nu}) \tag{1} $$ follows from using the Lorentz gauge then? Are we able to prove ##(1)##?
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