OOOHHH, I understand now, so if I use this equation instead of the conservation of KE, which I did before, I have the equations:
m(A)v(1)+m(B)v(2)=m(A)v'(1)+m(B)v'(2) and v(1)-v(2)=v'(2)-v'(1)
then I solve for either v'(1) or v'(2) and cancel out where the velocity is zero at v(2)...
the diagram is simply two balls (of masses mA and mB) suspended on two separate pendulums of equal length L=.3 m with the lighter ball (ball mA) held up at 66 degrees to the left.
since 1/2mv^2=mgh. I figured that I could place L-Lcos(theta) to make the height dependent on the angle. after...
Homework Statement
Two balls, of masses mA=45g and mB=65g, are suspended as shown in figure 9-53. The lighter ball is pulled away to a 66 degree angle with the vertical and released. (a.) What is the velocity of the lighter ball before impact? (b.) What is the velocity of each ball after the...