Recent content by Joshrk22

Simple trigonometry.. Opposite side = 30 Adjacent side = 100 Tan theta = opp divided by adjacent To find the angle, you'd take the tangent inverse of it. Tan-1 = 30/100 Which produces 17

What the heck? I just redid the calculation and got the same answer you just got. It must be 402,123, I must've made a mistake earlier. But I do believe that is the correct answer.

Well I did it using vectors and then by using a "whiz wheel" and both answers came out the same. You got 104 which is correct, but you can't just take the tan-1 of that. You have to take tan-1 of .3 because 30/100 = .3. That gives you 17 degrees but now if you are heading west and the wind is...

Frictional force = coefficient of friction * normal force Fn = mg = 73 * 9.8 = 715.4 N Ff = 460 N 460 N = uk * 715.4 N uk = .64

Nope. If you push against the wall with a force of 50 Newtons, the wall pushes back on you with a force of 50 Newtons. This is how a scale works.

Hmm, I got 287 degrees. Check your work again.

Use x = x0 + v0t + .5at^2 The car is not accelerating so all you need is x = v0t. Plug in your values... 45 = 15t t = 3 seconds Using x = .5gt^2 x = .5 * (9.8) * 3^2 x = 44.1 m

Okay well F - Ff = m*a. F = 750 N Ff = 341 750 - 341 = 290 * a a = 1.41 m/s Then the force of each blocking pushing on each other is equal because of Newton's 3rd law. So the Force on the first block minus the force of friction is equal to the force of one block on another. F - Ff = 409 N...

I took the x and y components of each vector and used x=vt. I then found the x and y components of the distance. I found the change in distances of each vector to get the resultant vector (distance). I then used x = .5at^2 and used the time above to get 1.5 m/s/s at 60 degrees. But I think I...

<4,0> + <1,0> produces <5,0> <1,0> + (-4,0> produces <-3,0>

I also used v=at and x=.5at^2. I now came up with 1.5 m/s/s at 60 degrees. So now I'm stuck between which answer it is.. But I do believe it's 60 degrees.

Hmm, I came up with .8 m/s/s also, and I did that even before I looked at your answer, so I don't know.

What's the correct answer?

captainjack, I came up with an answer of 128,000 J*s. You've done everything right so far, except in your first post you didn't calculate angular velocity correctly, but you have in your second post. Plug everything in and you should arrive at 128,000 (kg * m^2)/s or J*s

Yep, and she tried to tell us that none of them were "Does Not Exist..." Hah!