Recent content by Joshua A

  1. J

    What is the Period of a Physical Pendulum with a Horizontal Knife-Edge Pivot?

    Thank you! I figured out the question now. Hint for anyone who may stumble upon this thread in the future: when using the equation on the HyperPhysics page, note that it says Isupport. Use the parallel-axis theorem to help you find this.
  2. J

    What is the Period of a Physical Pendulum with a Horizontal Knife-Edge Pivot?

    Homework Statement A thin 0.50-kg ring of radius R = 0.60 m hangs vertically from a horizontal knife-edge pivot about which the ring can oscillate freely. If the amplitude of the motion is kept small, what is the period? Homework Equations T = 2pi / ω Not sure what others... The Attempt...
  3. J

    Why Is the Calculated Angular Momentum of the Pucks Zero?

    Angular velocity? s-1 (or rad/s - normally, as far as I know, rad isn't specified) Angular momentum is kg m2/s
  4. J

    Why Is the Calculated Angular Momentum of the Pucks Zero?

    The direction of the angular momentum vectors should be the same as the angular velocity vectors. I had assumed that the direction of the angular velocity vector would be in the direction of the motion of the puck (i.e. along the t axis). Looking back through my textbook, they do not actually...
  5. J

    Why Is the Calculated Angular Momentum of the Pucks Zero?

    Homework Statement Three small, identical 0.70-kg pucks are attached to identical 0.50-m strings, tied together at a common center as shown in (Figure 1) . Pucks are whirled in circular motion at angular speed 3.0 s-1 What is the magnitude of the angular momentum of the system about the...
  6. J

    Acceleration and Gravity with Circular Motion

    I was unaware of this. Does the centripetal acceleration always represent the net acceleration? (Would the net force represent the centripetal force in that case as well?)
  7. J

    Acceleration and Gravity with Circular Motion

    I can use conservation of energy to find the final velocity: mgh = 1/2mv2 so v = sqrt(2gh) I know that centripetal acceleration, ac can be found using: ac = v2/r but h and r are the same, so... ac = 2g = 19.6m/s2 So the centripetal acceleration is 2g. At the bottom of the bowl, there is no...
  8. J

    Acceleration and Gravity with Circular Motion

    I'm not quite sure what you mean... If I choose an angle of 5 degrees from the vertical, then the tangential acceleration of the ice cube will be 9.8m/s2 * cos(5) = 9.76m/s2. The component of the acceleration due to gravity perpendicular is 9.8m/s2 * sin(5) = 0.85m/s2 in the direction away from...
  9. J

    Acceleration and Gravity with Circular Motion

    Homework Statement You hold a small ice cube near the top edge of a hemispherical bowl of radius 100 mm. You release the cube from rest. What is the magnitude of its acceleration at the instant it reaches the bottom of the bowl? Ignore friction. Homework Equations ΣF = ma Fg = mg The Attempt...
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