Hi,
My teacher tasked me with a complex waveform question, i have looked for some time to find out how to tackle these, but i still do not know where to begin.
Any help would be greatly appreciated, not look for an answer just a method.
$$i=12sin(40*\pi t) + 4sin(120* \pi t - /3\pi) + 2sin(200...
The $$\sin(x)=-\frac{1}{2}$$ is a negative so will be out of the 0<=x<=180 range ?
The $$\sin(x)=1$$ will stay however ?
Then the sin(x) =1 can be entered into the cos2(x) + sin(x) = sin2(x) equation afterwards ?
Thanks
Using the equation cos2 + sin2 = 1,
i think the cos2(x) can be substituted for ( 1-sin2(x) )
which changes the equation to 0=-2sin2(x) + sin(x) +1
from there i factorised using the quadratic formulea (A=(-2), B=1, C=1)
this left me with sin(x) = -1/2 or 1
I'm not confident on my maths here...
Hello,
My teacher gave me some trig identity homework and it has completely stumped me :confused:.
Would be really grateful for some help, thanks!
The question is;
Solve the equation cos2(x) + sin(x) = sin2(x) for 0o<=x<=180o
I wasn't sure how to enter the degree symbol so i added ^0.