Recent content by JPorkins
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J
MHB Complex wave forms and fundamentals.... Very very stuck
Hi, My teacher tasked me with a complex waveform question, i have looked for some time to find out how to tackle these, but i still do not know where to begin. Any help would be greatly appreciated, not look for an answer just a method. $$i=12sin(40*\pi t) + 4sin(120* \pi t - /3\pi) + 2sin(200...- JPorkins
- Thread
- Complex Forms Fundamentals Stuck Wave
- Replies: 1
- Forum: General Math
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MHB Trig Identity Problem: Solve cos2(x) + sin(x) = sin2(x) for 0^0<=x<=180^0
Wow, you made it very simple ! I wish my teacher was as good as you aha. Thank you very much !- JPorkins
- Post #9
- Forum: General Math
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MHB Trig Identity Problem: Solve cos2(x) + sin(x) = sin2(x) for 0^0<=x<=180^0
At 90 degrees sin(x) = 1 ? Whether this is correct relevant to the question I'm not sure though !- JPorkins
- Post #7
- Forum: General Math
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MHB Trig Identity Problem: Solve cos2(x) + sin(x) = sin2(x) for 0^0<=x<=180^0
The $$\sin(x)=-\frac{1}{2}$$ is a negative so will be out of the 0<=x<=180 range ? The $$\sin(x)=1$$ will stay however ? Then the sin(x) =1 can be entered into the cos2(x) + sin(x) = sin2(x) equation afterwards ? Thanks- JPorkins
- Post #5
- Forum: General Math
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J
MHB Trig Identity Problem: Solve cos2(x) + sin(x) = sin2(x) for 0^0<=x<=180^0
Using the equation cos2 + sin2 = 1, i think the cos2(x) can be substituted for ( 1-sin2(x) ) which changes the equation to 0=-2sin2(x) + sin(x) +1 from there i factorised using the quadratic formulea (A=(-2), B=1, C=1) this left me with sin(x) = -1/2 or 1 I'm not confident on my maths here...- JPorkins
- Post #3
- Forum: General Math
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J
MHB Trig Identity Problem: Solve cos2(x) + sin(x) = sin2(x) for 0^0<=x<=180^0
Hello, My teacher gave me some trig identity homework and it has completely stumped me :confused:. Would be really grateful for some help, thanks! The question is; Solve the equation cos2(x) + sin(x) = sin2(x) for 0o<=x<=180o I wasn't sure how to enter the degree symbol so i added ^0.- JPorkins
- Thread
- Identity Trig
- Replies: 9
- Forum: General Math