Recent content by jr4life

Fpushing-(0.5)(9.8m)=0 Fpushing-4.9m=0 Fpushing=4.9m??

ok, i understand why it equals zero now but when you use that equation would it be friction=(0.5)(9.8m) and which two equations are you referring to?

mg-Fnormal=0 this is where i get confused with x because they are not in equilibrium so they wouldn't equal 0 Fpushing-friction=?? idk

in x direction it would be (mass)(0) so resultant force would be 0, because acceleration would be 0 due to constant velocity and in y direction (mass)(9.8) and then i don't really know what you could do with that...

In the x direction is the pushing force and force of friction and in the y direction is force of gravity on a box whos mass is not given and the normal force, i think the lack of given numbers is confuing me

no they didnt give the mass of the block, that is why I am so confused my teacher said something about sigma Fx=0 and sigma Fy=0 but i don't know what to do with those numbers, all i know is velocity is constant which makes acceleration 0 which makes force of x and y 0, but after that I am lost

Homework Statement The block is pushed to the right at a constant velocity. If the coefficient of kinetic friction is 0.5, what is the magnitude of the pushing force? Homework Equations I don't know... The Attempt at a Solution