thanks for the advice
so if f(z) = lz(z) and g(x)=3-e^-x
f'(z) = 1/z right? because derivative of ln x = 1/x.
and g'(x) = 3-(-1)e^x because derivative of e^x = e^x
not sure about that last line i wrote...
and then i would plug the answer for g'(x) into the 1/z in place of z?
my mistake. we're learning about chain, product, and quotient rule all at once so i got confused.
our professor was teaching us to separate the problem into two pieces, so i know to make it something like
f(x) = ln(z) and f(z)=3-e^(-x))
then the derivative of f(x) would be 1/z and you'd...
we're learning about the product rule and i understand it in class but I'm having a really hard time not making mistakes in my work, plus the ln is throwing me off...my homework is for accuracy too :frown: PLEASE help!