Recent content by junaidnawaz
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J
Undergrad Does applying arccos() to both sides of an inequality preserve its relation?
I wounder if its not a stupid question ... :P- junaidnawaz
- Post #8
- Forum: Set Theory, Logic, Probability, Statistics
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J
Undergrad Does applying arccos() to both sides of an inequality preserve its relation?
|\gamma| \leq \cos ( \beta ) When I take arccos() on both sides, it becomes \arccos( |\gamma| ) \geq \beta however, i want to keep \beta on right side, and i want to keep the relational operator as \leq , i.e., x \leq \beta what would be x ??- junaidnawaz
- Post #7
- Forum: Set Theory, Logic, Probability, Statistics
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J
Undergrad Does applying arccos() to both sides of an inequality preserve its relation?
Thank you. if |\gamma| \leq \cos( \beta ) then x \leq \beta can i find "x", by keeping the RHS fixed to \beta is this possible to find x ?? by keeping RHS and relation operator the same ??- junaidnawaz
- Post #5
- Forum: Set Theory, Logic, Probability, Statistics
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J
Undergrad Does applying arccos() to both sides of an inequality preserve its relation?
Thx v much for your reply. in my case, the range of parameters is as, 0 \leq \beta \leq \pi /2 -1 \leq \gamma \leq +1 by taking arccos() on both-sides, would it change the operator (from \leq to \geq ) or would it remain same ??- junaidnawaz
- Post #3
- Forum: Set Theory, Logic, Probability, Statistics
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Undergrad Does applying arccos() to both sides of an inequality preserve its relation?
Please help me to confirm, weather the following step is correct |\gamma| \leq \cos (\beta) \arccos (|\gamma|) \leq \beta does taking the arccos() on both sides of equation changes the relational operator??- junaidnawaz
- Thread
- Inequalities Trigonometric
- Replies: 9
- Forum: Set Theory, Logic, Probability, Statistics