|\gamma| \leq \cos ( \beta )
When I take arccos() on both sides, it becomes
\arccos( |\gamma| ) \geq \beta
however, i want to keep \beta on right side, and i want to keep the relational operator as \leq , i.e.,
x \leq \beta
what would be x ??
Thank you.
if
|\gamma| \leq \cos( \beta )
then
x \leq \beta
can i find "x", by keeping the RHS fixed to \beta
is this possible to find x ?? by keeping RHS and relation operator the same ??
Thx v much for your reply.
in my case, the range of parameters is as,
0 \leq \beta \leq \pi /2
-1 \leq \gamma \leq +1
by taking arccos() on both-sides, would it change the operator (from \leq to \geq ) or would it remain same ??
Please help me to confirm, weather the following step is correct
|\gamma| \leq \cos (\beta)
\arccos (|\gamma|) \leq \beta
does taking the arccos() on both sides of equation changes the relational operator??