Recent content by June W.

I'm not quite sure I follow you. I calculated the unit vector for T_bd as follows: B: <1.9, 0, 2.5> D: <1.9, 3.2, 0> BD = D - B BD = <0, 3.2, -2.5> n_bd = <0, 3.2, -2.5> / (3.2^2 + 2.5^2)^.5 T_bd = n_bd * T_bd T_bd = <0, .7880, -.6156>Am I messing up the initial values for B and D?

Homework Statement The right angle boom which supports the 230-kg cylinder is supported by three cables and a ball-and-socket joint at O attached to the vertical x-y surface. Determine the reactions at O and the cable tensions. Homework Equations M [/B]= r x F unit vector =...

So the vector pointing in the first quadrant no longer means the signs are always positive - I'll have to check the direction of rotation? The slope of the line of action is m = 2/3. Using the point (1,4), I solved for the equation of the line, which I got to be y = (2/3)x + (10/3). The slope...

Aren't the X and Y components of F both positive? I don't understand how they're in opposite directions; they're perpendicular to each other. Once I get the X and Y components of F, if I don't add them, what do I do with them? I tried to find the perpendicular distance d between the point B...

1. Because the squares are 1x1, I counted the squares and found the triangle to have sides of length 2 and 3. Then I used inverse tangent to sole for theta. (Apparently incorrectly. Now I get theta equal to 33.69 degrees). 2. I assumed they were added together based on an in-class example. I...

Homework Statement There is a copy of the problem in the picture with the graph. Homework Equations M = F*d, M = Fxr, F_x = Fcos(theta), F_y = Fsin(theta) where theta is measured off the positive X axis, The Attempt at a Solution I tried splitting the force vector into X and Y components and...

Thank you so much! That make so much more sense! I couldn't figure out what I was missing in class but that was probably it. Thanks!

Sorry, I'm still not getting it. Do I need to find the slope of the line of action? I don't know how to find where d intersects the line. I know all three angles in the triangle formed by a line perpendicular to the line of action, but I don't know the lengths of any of the sides. Is there a...

Is the line of action extended along the angle they provided (66 degrees into the second quadrant from the y axis)? What do I use to find the shortest distance? I know it intersects the dashed red line at a 90 degree angle, but I don't know what to do with that information.

Am I supposed to use r and theta to find d? I'm still confused.

The definition in my book (as best I can make it) is that "moment" is really the same as "torque," so the moment is a vector perpendicular to the plane of the body in question. So I don't need to split the force into X and Y components? How does that work? I know it's possible to calculate the...

Isn't the distance for a moment arm the distance between corresponding coordinates? So if the vector tail were at (2,4) and moment were being measured with respect to the origin, wouldn't the distances be 2 units of distance in the X direction and 4 units of distance in the Y direction? I know...

Homework Statement This problem is from WileyPLUS. I've been looking through my book, but none of the methods they present work for me. I guess I just don't know how to use them properly. Determine the moments of the 5.6-kN force about the point O and about point B. Homework Equations I...