Im sorry i don't understand ... ! Can u elaborate a bit more . what last digit ??
Ive skimmed through some textbooks and websites ... What i don't understand is why some quote the uncertainty for a regular metre rule as
+/-0.05mm and others as +/-0.1mm ... and what's the difference between...
This is a question about practical physics ... if its posted in the wrong section my sincere apologies !
How do i decide the least count of a measuring device such as an ammeter (analog) ?
I know that the least count is the smallest division of measurement ... but why do people...
got it ! thank u ! and bless u ! :)
one more question how do other folks here draw those nifty little resistors ?? I can't imagine doing that on mspaint ? do they use some kinda physics software package or something ?
Loops 2 and 3 were confusing (i made guesses but i didnt really choose a direction , infact i thought i was going clockwise for all the loops ) ... can u explain why i got the results that i got for 2 and 3 ... ? or may be explain how u would go about solving loops 2 and 3
i = i1 +i3 = i4
In Loop 1 ,
15 -i3*6 - i4*10 = 0 (im not sure about this , its grounded ?)
In Loop 3,
i1*12 - 6*i3 = 0
In Loop 2
i2*40 - i4 * 10 = 0
That looks wrong to me oh but what the heck ...
part of the problem is that I don't understand enough to ask these questions !
PS How do other members link pics to Circuit diagrams and Free Body Diagrams ... are there any software for that which i could use ?
So in essence I've to choose a direction using which ill traverse the loop and in doing so if the potential is decreasing the emf is positve(again conventional current) and viceversa ... and ill be using that very same direction and checking to see if the voltage drop in a resistor is positive...
I understand Kirchoffs law ( its statement and what it means) but when it comes to application of the laws I am lost ...
Heres what i gathered from some books :
1. I have to choose a direction . Any current through a resistor that opposes this direction is -IR , the ones that follow this...