Okay, yes, I get that. But you weren't explaining it like that earlier. Usually when I think of Net force I think of all the forces being added up (in this case, the external and the electrical field force).
Right. I guess in order for me to answer this question, I just don't see that why I would need to think about it so in depthly in order to answer this problem. If I inherently thought the forces were equal and opposite then I would just assume that the proton or electron never moved at all.
I...
I feel like I'm going in circle then at this point with Newton's 2nd law. If acceleration is 0, would that not make force 0?
I understand how you were saying that the original external force would have to be slightly greater than the electrical force for the proton/electron to move to begin...
I know that the forces are the same because the work is the same. W=F*d. And I know the answer is E to this question. So I know that forces are the same I just don't understand WHY.
I also don't know if this question is asking about the work done by the e-field or the work done by the external...
Okay rather than stating to me what I need to know, why don't you explain to me why I don't know what I don't know. I don't know why the accelerations are different or the same. Or if that's even relevant to the question at all. I've worked on this problem for about an hour and I don't...
Because of F=ma. If the masses are different then either the force is different or the acceleration has to compensate to make the forces be the same and I don't know why the accelerations are different.
Homework Statement
A charged capacitor consists of two large flat plates, one with positive charge +Q and the other negative charge -Q. An external agent trans an electron from the positive plate to the negative and also transfers a proton from the negative plate to the positive plate. There is...
Homework Statement
Q1<------>Q2<------>Q3
In the above figure, the distance between Q1 and Q2 is equal to the distance between Q2 and Q3. That distance is R=1.5 m.
Q1= 2.24x10-6 C, Q2=+Q1 and Q3=-Q1.
Calculate the total force on Q1. Give your answer with a positive number for a force...