Recent content by JustAStudent

  1. JustAStudent

    Work to move electron/proton between the plates of a charged capacitor?

    Okay, yes, I get that. But you weren't explaining it like that earlier. Usually when I think of Net force I think of all the forces being added up (in this case, the external and the electrical field force).
  2. JustAStudent

    Work to move electron/proton between the plates of a charged capacitor?

    Right. I guess in order for me to answer this question, I just don't see that why I would need to think about it so in depthly in order to answer this problem. If I inherently thought the forces were equal and opposite then I would just assume that the proton or electron never moved at all. I...
  3. JustAStudent

    Work to move electron/proton between the plates of a charged capacitor?

    I don't think 'worry' is the right answer. It's the fact that Force=0 that confuses me if we're relating it back to Newton's 2nd law.
  4. JustAStudent

    Work to move electron/proton between the plates of a charged capacitor?

    I feel like I'm going in circle then at this point with Newton's 2nd law. If acceleration is 0, would that not make force 0? I understand how you were saying that the original external force would have to be slightly greater than the electrical force for the proton/electron to move to begin...
  5. JustAStudent

    Work to move electron/proton between the plates of a charged capacitor?

    So would that make the force=0 then? For both.
  6. JustAStudent

    Work to move electron/proton between the plates of a charged capacitor?

    Okay so in that case the total acceleration then is constant. Or 0. . . yes?
  7. JustAStudent

    Work to move electron/proton between the plates of a charged capacitor?

    Also, I thought because force has mass in it's equation (F=ma) that it would be related.
  8. JustAStudent

    Work to move electron/proton between the plates of a charged capacitor?

    So why is it equal and opposite? If they were equal, how could the object be moving?
  9. JustAStudent

    Work to move electron/proton between the plates of a charged capacitor?

    I know that the forces are the same because the work is the same. W=F*d. And I know the answer is E to this question. So I know that forces are the same I just don't understand WHY. I also don't know if this question is asking about the work done by the e-field or the work done by the external...
  10. JustAStudent

    Work to move electron/proton between the plates of a charged capacitor?

    Okay rather than stating to me what I need to know, why don't you explain to me why I don't know what I don't know. I don't know why the accelerations are different or the same. Or if that's even relevant to the question at all. I've worked on this problem for about an hour and I don't...
  11. JustAStudent

    Work to move electron/proton between the plates of a charged capacitor?

    Because of F=ma. If the masses are different then either the force is different or the acceleration has to compensate to make the forces be the same and I don't know why the accelerations are different.
  12. JustAStudent

    Work to move electron/proton between the plates of a charged capacitor?

    Homework Statement A charged capacitor consists of two large flat plates, one with positive charge +Q and the other negative charge -Q. An external agent trans an electron from the positive plate to the negative and also transfers a proton from the negative plate to the positive plate. There is...
  13. JustAStudent

    Calculate the total force on Q1

    Okay, so I'm thinking of it incorrectly then. Force of Q3 ON Q1 means which way Q1 is going (attraction v repulsion) and not which way Q3 is going?
  14. JustAStudent

    Calculate the total force on Q1

    Homework Statement Q1<------>Q2<------>Q3 In the above figure, the distance between Q1 and Q2 is equal to the distance between Q2 and Q3. That distance is R=1.5 m. Q1= 2.24x10-6 C, Q2=+Q1 and Q3=-Q1. Calculate the total force on Q1. Give your answer with a positive number for a force...
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