Recent content by JustSam

Thanks for the additional explanation. For some reason, I'm having trouble understanding the color charge concept.

I'm wondering now if this is just the baryon number?

Okay. A 0 Red, 0 Blue, 0 Green particle can be its own antiparticle, but a +1 Red, +1 Blue, +1 Green particle cannot be its own antiparticle. Is this what you mean? Is there a name for the +1 Red, +1 Blue, +1 Green color charge combination, like +1 Colorless or +1 Colorfull? That way, free...

Thanks, that makes a lot of sense. To what extent does a +1 Red, +1 Blue, +1 Green particle differ in color charge from a 0 Red, 0 Blue, 0 Green particle? Based on a three dimensional color space, I would say these are different, yet they both seem to be dumped into the same "colorless"...

I'm trying to understand quark color. Everyone seems to say that there are three quark colors, say Red, Blue, Green, that add up to uncolored. So why not just pick a basis, say Red and Blue, so that the color Green is equivalent to -1 Red plus -1 Blue?

I'm sure if I get something wrong, smart people will come and correct me, so here goes! I think the main progress is that more people appreciate Bell's complaint. In the 60's, Bell was a voice in the wilderness, with most everyone else completely satisfied with the understanding of quantum...

See https://www.physicsforums.com/showpost.php?p=2331535&postcount=17" for John Bell's writing about problems with quantum mechanical measurement.

If the electron is traveling in the x-direction, then the timing gives you the x-momentum, and the impact on the screen gives you the y-position and the z-position. I don't think there is any uncertainty principle involved in these three measurements, as they commute. It is only momentum and...

The body of the inner j loop is executed 1 + \lfloor \log_2 (n / i) \rfloor times for a given pass of the outer i loop. Now sum this over the different values of i from the outer loop.

What quantum states are "superpositions" depends on which basis one chooses for the Hilbert space. A definite |x-spin = +1/2> is just the superposition of |z-spin = -1/2> and |z-spin = +1/2> states. And surely the |x-spin = +1/2> state is physically meaningful.

Here is how John Bell characterized one aspect of the measurement problem, from his paper Quantum Mechanics for Cosmologists: It would seem that the theory is exclusively concerned with 'results of measurement' and has nothing to say about anything else. When the 'system' in question is the...

This is the part of quantum mechanics that no one has worked out yet. It's called the "measurement problem" because there isn't really any precise definition of what a measurement is, when it happens, and what takes place when a measurement happens. My personal view is that a measurement is...

Which is why it is important to have a precise definition of d(p). According to my second version, d(p) is the maximum number of solutions over all possible choices for N, so it makes sense that you can find particular values of N that have fewer than d(p) solutions. Perhaps "d(p,N) = exact...

Definitely don't stay at DeVry. Find a school for your bachelors where you will actually learn stuff. If they don't let you transfer credits, maybe at least you can still take new classes that are challenging and useful, instead of having to repeat classes in subjects you already know. If you...

Do the + and the - outputs of the first SGz filter lead to the same SGx filter, or does each output lead to a different SGx filter, so the system is set up like a tree? If there is just one linear sequence of filters, then they don't "record" anything - there is no way to tell whether they went...